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Dahasolnce [82]
3 years ago
5

Molecular mathematics

Chemistry
2 answers:
posledela3 years ago
8 0

Answer: Exactly what are you trying to say here?

butalik [34]3 years ago
6 0

Answer:

bruh what is the question

Explanation:

there is no question ;-;

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If 50 g of lead (of specific heat 0.11 kcal/kg ∙ C°) at 100°C is put into 75 g of water (of specific heat 1.0 kcal/kg ∙ C°) at 0
Contact [7]

Answer: The final temperature is 279.8K

Explanation:

heat_{absorbed}=heat_{released}

As we know that,  

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]         .................(1)

where,

q = heat absorbed or released

m_1 = mass of lead = 50 g

m_2 = mass of water = 75 g

T_{final} = final temperature = ?

T_1 = temperature of lead = 100^oC=373K

T_2 = temperature of water = 0^oC=273K

c_1 = specific heat of lead = 0.11kcal/kg^0C

c_2 = specific heat of water= 1.0kcal/kg^0C

Now put all the given values in equation (1), we get

50\times 0.11\times (T_{final}-373)=-[75\times 1.0\times (T_{final}-273)]

T_{final}=279.8K

Therefore, the final temperature of the mixture will be 279.8 K.

3 0
4 years ago
How to make bottled soda taste like fountain?
dybincka [34]
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4 0
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Thank you in advance!
Contact [7]

Answer:

nobody can answer this question because you have to draw model and you can't do it on here sorry .

Explanation:

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scoundrel [369]

Answer:  

1.  DNA copying mistakes made during cell division, exposure to ionizing radiation, exposure to chemicals called mutagens, or infection by viruses.

2.  both

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3 years ago
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