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4 years ago

Given h(×) =-3×+2,solve for x when h (×)=-4

Mathematics

2 answers:

ArbitrLikvidat [17]4 years ago

8 0

-3•-4+2 -3•-4=12 cause - times - = positive then add 2 so u get 14

MakcuM [25]4 years ago

7 0

Answer:14

Step-by-step explanation:

h(x)=-3x+2

h(-4)=-3(-4)+2

h(-4)=12+2

h(-4)=14

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Answer:

$38$ and $68$ .

Step-by-step explanation:

Let $x$ be the smaller one of the two number.

$x$ must be a positive integer. The other number would be $(x + 30)$ .

The question states that the product of the two numbers is $2584$ . In other words:

$x\, (x + 30) = 2584$ .

Rearrange this equation and solve for $x$ :

$x^{2} + 30\, x - 2584 = 0$ .

The first root of this quadratic equation would be:

$\begin{aligned}x_{1} &= \frac{(-30) + \sqrt{30^{2} - 4 \times (-2584)}}{2} \\ &= \frac{(-30) + \sqrt{900 + 10336}}{2} \\ &= \frac{(-30) + \sqrt{11236}}{2} \\ &= \frac{(-30)}{2} + \sqrt{\frac{11236}{2^{2}}} \\ &= (-15) + \sqrt{2809} \\ &= (-15) + 53 \\ &= 38 \end{aligned}$ .

Similarly, the second root of this quadratic equation would be:

$\begin{aligned}x_{1} &= \frac{(-30) - \sqrt{30^{2} - 4 \times (-2584)}}{2} \\ &= (-15) - 53 \\ &= -68\end{aligned}$ .

Since the question requires that both numbers should be positive, $x > 0$ . Therefore, only $x = 38$ is valid.

Hence, the two numbers would be $38$ and $(38 + 30)$ , which is $68$ .

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