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Hoochie [10]
3 years ago
15

Given h(×) =-3×+2,solve for x when h (×)=-4

Mathematics
2 answers:
ArbitrLikvidat [17]3 years ago
8 0
-3•-4+2 -3•-4=12 cause - times - = positive then add 2 so u get 14
MakcuM [25]3 years ago
7 0

Answer:14

Step-by-step explanation:

h(x)=-3x+2

h(-4)=-3(-4)+2

h(-4)=12+2

h(-4)=14

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8 0
2 years ago
Read 2 more answers
What is the sum of three tenths plus thirty nine hundredths equals blank a thirty six hundredths b forty two hundredths c sixty
ad-work [718]

Answer:c- sixty nine hundredths

Step-by-step explanation:

three tenths can be expressed in decimal as 3/10

thirty nine hundredths can be expressed in decimal as 39/100

Therefore the sum of three tenths plus thirty nine hundredths equals

3/10 +39/100

We first find the l.c.m of the two fractions equals 100 so we have 100 as the denominator

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3 0
3 years ago
In a random sample of 5 residents of the state of Texas, the mean waste recycled per person per day was 1.9 pounds with a standa
sammy [17]
<h2>Answer with explanation:</h2><h2 />

The confidence interval for population mean is given by :-

\overline{x} \pm\ t_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}

Given : Sample size : n= 5, since n<30 , so the test we use here is t-test.

Sample mean : \overline{x}=1.9\text{ pounds}

Standard deviation: \sigma=0.89\text{ pounds}

Significance level : 1-\alpha:1-0.99=0.01

By using the standard normal distribution table , the critical value corresponds to the given significance level will be :-

t_{n-1,\alpha/2}=t_{5-1,0.01/2}=t_{4,0.005}=4.604

Now, the 99% confidence interval for the mean waste recycled per person per day for the population of Texas will be :-

1.9\pm\ (4.604)\dfrac{0.89}{\sqrt{5}}\\\\\approx1.9\pm1.832\\\\=(1.9-1.832,1.9+1.832)=(0.068,\ 3.732)

Hence, the 99% confidence interval for the mean waste recycled per person per day for the population of Texas  = (0.068, 3.732)

5 0
3 years ago
Which place value would you look to compare 225998 and 225988
Jobisdone [24]
225998 225988
I believe it is the tenths place
(the bold digits)
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3 years ago
Find the proportion of observations from a standard Normal distribution that falls in each of the following regions. -2.31 &lt;
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\mathbb P(-2.31
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