You can always match 4 points using a cubic polynomial. A graphing calculator can find a cubic regression equation for you. This set of points is matched by
.. y = x^3 +3x^2 +5x +3
.. y = x^3 +3x^2 +5x +3
In the diagram shown, line mm is parallel to line nn. Cruz says that ∠4∠4 and ∠6∠6 are congruent angles. Is he correct? Why or w
hy not?
a) Yes, because they are both obtuse angles
b)Yes, because ∠4∠4 and ∠7∠7 are congruent corresponding angles, and ∠6∠6 and ∠7∠7 are vertical angles.
c)No, because ∠4∠4 and ∠6∠6 are not right angles.
d)No, because ∠4∠4 and ∠5∠5 are not congruent, and ∠5∠5 and ∠6∠6 are not congruent.
a) Yes, because they are both obtuse angles
b)Yes, because ∠4∠4 and ∠7∠7 are congruent corresponding angles, and ∠6∠6 and ∠7∠7 are vertical angles.
c)No, because ∠4∠4 and ∠6∠6 are not right angles.
d)No, because ∠4∠4 and ∠5∠5 are not congruent, and ∠5∠5 and ∠6∠6 are not congruent.
2 answers:
You might be interested in
Well, first off, let's find what is the slope of BC
now, a line perpendicular to that one, will have a negative reciprocal slope, thus
now, we know the slope "m" of AB is -2 then, thus
now, a line perpendicular to that one, will have a negative reciprocal slope, thus
now, we know the slope "m" of AB is -2 then, thus
Answer: 
Explanation: For this, it is often best to find the horizontal asymptote, and then take limits as x approaches the vertical asymptote and the end behaviours.
Well, we know there will be a horizontal asymptote at y = 0, because as x approaches infinite and negative infinite, the graph will shrink down closer and closer to 0, but never touch it. We call this a horizontal asymptote.
So we know that there is a restriction on the y-axis.
Now, since we know the end behaviours, let's find the asymptotic behaviours.
As x approaches the asymptote of 7⁻, then y would be diverging out to negative infinite.
As x approaches the asymptote at 7⁺, then y would be diverging out to negative infinite.
So, our range would be:
Explanation: For this, it is often best to find the horizontal asymptote, and then take limits as x approaches the vertical asymptote and the end behaviours.
Well, we know there will be a horizontal asymptote at y = 0, because as x approaches infinite and negative infinite, the graph will shrink down closer and closer to 0, but never touch it. We call this a horizontal asymptote.
So we know that there is a restriction on the y-axis.
Now, since we know the end behaviours, let's find the asymptotic behaviours.
As x approaches the asymptote of 7⁻, then y would be diverging out to negative infinite.
As x approaches the asymptote at 7⁺, then y would be diverging out to negative infinite.
So, our range would be: