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3 years ago

Help with expressing a graph as an inequality ?

Mathematics

1 answer:

IRINA_888 [86]3 years ago

6 0

Its been a little while, but im pretty sure it is y (greater than or equal to sign) 3/4x - 3

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Ps help! will give brainliest answer

andrew-mc [135]

1. 12

2. 96 is greater

3. 19

3 0

2 years ago

amoni is painting a room. He used 2/3 of a gallon of paint to cover 1/4 of a wall. how much paint for the whole wall

sukhopar [10]

Answer:

<u>8/3 or 2 2/3 gallons of paint</u>

Step-by-step explanation:

If 2/3 of paint covers 1/4 of the wall, you must multiply 2/3 by 4 to get 4/4 (the whole wall).

2/3 x 4 = 8/3 or 2 2/3

5 0

2 years ago

Find the angle between u =the square root of 5i-8j and v =the square root of 5i+j.

fenix001 [56]

Answer:

The angle between vector $\vec{u} = 5\, \vec{i} - 8\, \vec{j}$ and $\vec{v} = 5\, \vec{i} + \, \vec{j}$ is approximately $1.21$ radians, which is equivalent to approximately $69.3^\circ$ .

Step-by-step explanation:

The angle between two vectors can be found from the ratio between:

their dot products, and
the product of their lengths.

To be precise, if $\theta$ denotes the angle between $\vec{u}$ and $\vec{v}$ (assume that $0^\circ \le \theta < 180^\circ$ or equivalently $0 \le \theta < \pi$ ,) then:

$\displaystyle \cos(\theta) = \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|}$ .

<h3>Dot product of the two vectors</h3>

The first component of $\vec{u}$ is $5$ and the first component of $\vec{v}$ is also

The second component of $\vec{u}$ is $(-8)$ while the second component of $\vec{v}$ is $1$ . The product of these two second components is $(-8) \times 1= (-8)$ .

The dot product of $\vec{u}$ and $\vec{v}$ will thus be:

$\begin{aligned} \vec{u} \cdot \vec{v} = 5 \times 5 + (-8) \times1 = 17 \end{aligned}$ .

<h3>Lengths of the two vectors</h3>

Apply the Pythagorean Theorem to both $\vec{u}$ and $\vec{v}$ :

$\| u \| = \sqrt{5^2 + (-8)^2} = \sqrt{89}$ .
$\| v \| = \sqrt{5^2 + 1^2} = \sqrt{26}$ .

<h3>Angle between the two vectors</h3>

Let $\theta$ represent the angle between $\vec{u}$ and $\vec{v}$ . Apply the formula $\displaystyle \cos(\theta) = \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|}$ to find the cosine of this angle:

$\begin{aligned} \cos(\theta)&= \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|} = \frac{17}{\sqrt{89}\cdot \sqrt{26}}\end{aligned}$ .

Since $\theta$ is the angle between two vectors, its value should be between $0\; \rm radians$ and $\pi \; \rm radians$ ( $0^\circ$ and $180^\circ$ .) That is: $0 \le \theta < \pi$ and $0^\circ \le \theta < 180^\circ$ . Apply the arccosine function (the inverse of the cosine function) to find the value of $\theta$ :

$\displaystyle \cos^{-1}\left(\frac{17}{\sqrt{89}\cdot \sqrt{26}}\right) \approx 1.21 \;\rm radians \approx 69.3^\circ$ .

3 0

2 years ago

I’m plz help fast thanks <br><br><br><br> 16

nataly862011 [7]

Answer:

1/2 <3/4

Step-by-step explanation:

1/2 vs 3/4

We need a common denominator of 4

1/2*2/2 vs 3/4

2/4 vs 3/4

Since the denominators are the same, we compare the numerators

2 <3 so

2/4 < 3/4

1/2 <3/4

5 0

3 years ago

in a window display at a flower shop, there are 3 spots for 1 plant each. to fill these 3 spots, adam has 7 plants to select fro

Andrej [43]

Answer: 210

Step-by-step explanation:

We know that the number of combinations of n things taken r at a time is given by :-

$C(n,r)=\dfrac{n!}{r!(n-r)!}$

So, number of ways to select 3 plants out of 7 = $C(7,3)=\dfrac{7!}{3!4!}=\dfrac{7\times6\times5\times4!}{6\times 4!}=7\times5=35$

Also number of ways to arrange them in 3 positions = 3! = 6

Now , total number of arrangements with 1 plant in each spot = (number of ways to select 3 plants out of 7) x (number of ways to arrange them in 3 positions)

= 35 x 6

=210

Hence, required number of ways = 210

5 0

2 years ago