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OLEGan [10]
3 years ago
15

How do you solve these problems? a. (2/7)x + 5= -21 and b. 1/2(18x-2)=0

Mathematics
1 answer:
Kryger [21]3 years ago
3 0
A is x=-91
B is x=1/9
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Find the common difference in the outputs to help find the missing outputs in the table
WINSTONCH [101]

Answer:

if you are trying to find the rest of A it would be adding by 1 because of the slope so: 5,6,7,8,9,10. The slope of B wouldbe .8 because it is increasing by .8 everytime so: 3.8,4.6,5.4,6.2,7.0

Step-by-step explanation:

B) 4.6-3.8= .8

5.4-4.6= .8

slope is .8

5.4+.8=6.2

6.2+ .8= 7.0


8 0
3 years ago
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I could use some help doing this simple math problem lol.
alexira [117]
D:k-9\geq 0 \wedge k\geq0\\
D:k\geq 9 \wedge k\geq0\\
D:k\geq 9\\
\sqrt{k-9}-\sqrt k=-1\\
\sqrt{k-9}=-1+\sqrt k\\
k-9=(-1+\sqrt k)^2\\
k-9=1-2\sqrt k+k\\
2\sqrt k=10\\
\sqrt k =5\\
k=25


7 0
3 years ago
What is the measure of an exterior angle of a rectangle of a regular 11-sided polygon?
horsena [70]

180 \div 11 =
4 0
4 years ago
Read 2 more answers
Select the correct answer. A triangle has vertices (-1, 2), (3, 1), and (7, 2). What is the approximate perimeter of th...
Eva8 [605]

Answer:

16.24 Units

Step-by-step explanation:

The perimeter of the triangle is the sum of the length of the sides of the triangle. Given the points on the vertices, the length of each side may be found using the formula

Length = √(x2 - x1)^2 + (y2 - y1)^2

Considering the pair (-1, 2), (3, 1), the length of that side

= √(3 -- 1)^2 + (1-2)^2)

= √(16 + 1)

= √17 units

Considering the pair (-1, 2), (7, 2), the length of that side

= √(7 -- 1)^2 + (2-2)^2)

= √(64)

= 8

Considering the pair  (3, 1),  and (7, 2), the length of that side

= √(7 - 3)^2 + (2  - 1)^2

= √(16 + 1)

= √17

Hence the perimeter of the triangle

= √17 + 8 + √17

= 4.12 + 8 + 4.12

= 16.24 Units

5 0
3 years ago
when a pen is sold at a discount of 15%, there is a gain of Rs 10. but if it is sold at 25% discount, there is a loss of Rs 2. f
LenaWriter [7]

Answer:

Rs 120.  

Step-by-step explanation:

10=0.85SP-CP; CP+10=0.85SP; SP=[CP+10]/0.85 Eq 1. Let SP= Selling Price and CP= Cost Price

-2 =0.75SP-CP; 0.75SP=C-2; SP=[CP-2]/0.75 Eq 2

[CP+10]/0.85=[CP-2]/0.75 : SP of Eq 1=SP of Eq 2

0.75[CP+10]=0.85[CP-2]

0.75CP+7.5=0.85CP-1.7

0.85CP-0.75CP=-1.7–7.5=9.2

0.10CP=9.2; CP=9.2/0.10

CP=Rs 92 Cost Price of pen

10=0.85SP-92; 0.85SP=92+10=102; SP=102/0.85=Rs 120 Marked Price of pen (answer)

From Eq2: -2=0.75SP-CP; 0.75SP=CP-2=92–2=90; SP=90/0.75=Rs120; -2=0.75(120)-CP; CP-2=0.75(120); CP-2=90; CP=90+2=Rs 92

Set CP of Eq 1=CP of Eq 2:

CP=0.85SP-10 from Eq 1; CP=0.75SP+2 from Eq 2;

0.85SP-10=0.75SP+2; 0.85SP-0.75SP=10+2=12

0.10SP=12; SP=12/0.10=Rs120 is the Marked Price(answer)

Normally, the Selling Price is the marked price. The seller will not disclose the Cost Price because it is the price when the item was acquired or procured, otherwise the buyer will ask for more discounts and based his buying price from the Cost Price if it is known. The calculated SP and CP satisfy both Eq 1 and Eq 2. Both Eq 1 and Eq 2 satisfy the given conditions of the problem above.

8 0
3 years ago
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