You can't simplify 11/20. hope that helped
Answer:
Part 1) The area of the figure is
Part 2) The perimeter of the figure is 
Step-by-step explanation:
Part 1) Find the area of the figure
we know that
The area of the figure is equal to the area of three squares
so
![A=3[4^2]=48\ cm^2](https://tex.z-dn.net/?f=A%3D3%5B4%5E2%5D%3D48%5C%20cm%5E2)
Part 2) Find the perimeter of the figure
we know that
The perimeter of the figure is equal to two times the length side of the square, plus the circumference of six semicircles ( or the circumference of three circles)
Remember that
The circumference of a circle is equal to

where
D is the diameter of the circle
In this problem

so
![P=2(4)+3[\pi(4)]=(8+12\pi)\ cm](https://tex.z-dn.net/?f=P%3D2%284%29%2B3%5B%5Cpi%284%29%5D%3D%288%2B12%5Cpi%29%5C%20cm)
simplify

To help you graph this, get y alone in both equations. If you don't have a graphing calculator, use the Desmos graphing calculator online.
So, you will end up graphing this:
y=8-x
y=(34/3)-(5/3)x
They will meet at (5,3)
Answer:
11 of 20p, 22 of 10p and 33 of 5p
Step-by-step explanation:
Eva has 20p, 10p and 5p coins, total of £6.05 = 605p
Let 20p=x, 10p=y, 5p=z
<u>Then</u>:
- 20x + 10y + 5z = 605
- y : x = 2 : 1 ⇒ x= y/2
- y : z = 2 : 3 ⇒ z= 3y/2
<u>Rewriting the first equation considering next two:</u>
- 10y + 10y + 7.5y = 605
- 27.5y = 605
- y= 605/27.5
- y= 22
- x= y/2 = 22/2 = 11
- z = 3y/2 = 3*11 = 33
<u>Answer:</u> 11 of 20p coins, 22 of 10p coins and 33 of 5p coins