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Nady [450]
3 years ago
9

Okay so Circle A is intersected by lines Lm and MO. What is the measure of Angle LMO

Mathematics
1 answer:
nata0808 [166]3 years ago
5 0
The answer is 48.5, did a question similar to this on a quiz and got it right
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Derman says, "I'm halfway through reading my book.if I read another 84 pages, I'll be two thirds of the way through my book." ho
Licemer1 [7]
I would say 504 basing it off of converting 2/3 into 4/6 and used sets of 84 to each be 1/6
6 0
3 years ago
Lilia wants to rewrite 10/25 as a percent she decided to represent 10/25 first in a picture a.)how many sets of 25 will she need
neonofarm [45]

Answer:

4 sets of 25

Step-by-step explanation:

100/25 = 4

Not sure what you are asking in the end.

7 0
3 years ago
Perform the following computations.You may use13≈0.333333,34= 0.75 and100301= 0.332226.(i). Compute13+34by using five significan
White raven [17]

Answer:

a. 1.0833

Absolute Error = 0.416667

Relative Error = 1.250002

b. 0.0011070

Absolute Error = 0.0011070

Relative Error = 0.003321

Step-by-step explanation:

Given

1/3 = 0.333333

3/4 = 0.75

100/301 = 0.332226

a.

1/3 + 3/4

= 0.333333 + 0.75

= 1.083333

= 1.0833 ------ Approximated to 5 significant digits

Absolute Error = |Real Value - Estimated Value|

Relative Error = Absolute Error/Real Value

Assume 1/3 to be the real value and 3/4 to be the estimated value

Absolute Error = |0.333333 - 0.75|

Absolute Error = |-0.416667|

Absolute Error = 0.416667

Relative Error = 0.416667/0.333333

Relative Error = 1.250002

b.

1/3 - 100/301

= 0.333333 - 0.332226

= 0.001107

= 0.0011070 ----- Approximated to 5 significant digits

Assume 1/3 to be real value and 100/301 to be estimated value

Absolute Error = 0.333333 - 0.332226

Absolute Error = 0.0011070

Relative Error = 0.0011070/0.333333

Relative Error = 0.003321

Absolute and relative errors are approximation errors and they are due to the discrepancy between an exact value and some approximation to them.

The absolute error is the magnitude of the difference between the exact value and the approximation. The relative error is the absolute error divided by the magnitude of the exact value

4 0
3 years ago
Solve the system of equations.<br> ​<br><br> 2x−9y=14<br> x=−6y+7<br> ​
ipn [44]

Step-by-step explanation:

put \: x \: into \: equation \: 1

2( - 6y + 7) - 9y = 14

- 12y + 14 - 9y = 14

- 21y + 14 = 14

- 21y = 14 - 14

- 21y = 0

\frac{ - 21y}{12}  =  \frac{0}{21}

y = 0

put \: y = 0 \: into \: equation \: 2

x = 6y + 7

x = 6(0) + 7

x = 0 + 7

x = 7

3 0
2 years ago
Read 2 more answers
What is the maximum amount of baggage that may be loaded aboard the airplane for the cg to remain within the moment envelope? we
Korvikt [17]
<span>You are to find the maximum amount of baggage that may be loaded aboard the airplane for the cg (center of gravity) to remain within the moment envelope.

In order to solve this, there is a graph that shows the load weight and the load moment of pilot and front passenger, fuel, rear passenger and passenger including the baggage. Using the given data such as pilot and front passenger 250, the load moment is 9 lbs/in, for the rear passenger at 400lbs, the load moment is 28.5 lbs/in, the fuel at 30 gal has a load moment of 2 lbs/in and oil at 8 quarters is 15 lbs. The total weight is 1,350 + 250 + 400 + 15 is 2015 lbs.</span>
6 0
3 years ago
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