Answer:
hey hope this helps
<h3 /><h3>Comparing sides AB and DE </h3>
AB =
![\sqrt{ {1}^{2} + {1}^{2} }](https://tex.z-dn.net/?f=%20%5Csqrt%7B%20%7B1%7D%5E%7B2%7D%20%2B%20%20%7B1%7D%5E%7B2%7D%20%20%7D%20)
![= \sqrt{2}](https://tex.z-dn.net/?f=%20%3D%20%20%5Csqrt%7B2%7D%20)
DE
![= \sqrt{ {(3 - 5)}^{2} + {(1 + 1}^{2} } \\ = \sqrt{ {( - 2)}^{2} + {(2)}^{2} } \\ = \sqrt{4 + 4} \\ = \sqrt{8} \\ = 2 \sqrt{2}](https://tex.z-dn.net/?f=%20%20%3D%20%5Csqrt%7B%20%7B%283%20-%205%29%7D%5E%7B2%7D%20%2B%20%20%7B%281%20%2B%201%7D%5E%7B2%7D%20%20%7D%20%20%5C%5C%20%20%20%3D%20%5Csqrt%7B%20%7B%28%20-%202%29%7D%5E%7B2%7D%20%20%2B%20%20%7B%282%29%7D%5E%7B2%7D%20%7D%20%20%5C%5C%20%20%20%20%3D%20%5Csqrt%7B4%20%2B%204%7D%20%20%5C%5C%20%20%3D%20%20%5Csqrt%7B8%7D%20%20%5C%5C%20%20%20%3D%202%20%5Csqrt%7B2%7D%20)
So DE = 2 × AB
and since the new triangle formed is similar to the original one, their side ratio will be same for all sides.
<u>scale factor</u> = AB/DE
= 2
It's been reflected across the Y-axis
<em>moved thru the translation of 3 units towards the right of positive x- axis </em>
for this let's compare the location of points B and D
For both the y coordinate is same while the x coordinate of B is 0 and that of D is 3
so the triangle has been shifted by 3 units across the positive x axis
Answer:
see explanation
Step-by-step explanation:
To find x use the sine ratio in the right triangle and the exact value
sin60° =
, then
sin60° =
=
=
( cross- multiply )
x
= 28
( divide both sides by
)
x = 28
-----------------------------------------------------------
To find y use the tangent ratio in the right triangle and the exact value
tan60° =
, then
tan60° =
=
=
( multiply both sides by y )
14
= y
( divide both sides by
)
y = 14
How many facts does it take to make triangles congruent? Only 3 if they are the right three and the parts are located in the right place.
SAS where 2 sides make up one of the three angles of a triangle. The angle must between the 2 sides.
ASA where the S (side) is common to both the two given angles.
SSS where all three sides of one triangle are the same as all three sides of a second triangle. This one is my favorite. It has no exceptions.
In one very special case, you need only 2 facts, but that case is very special and it really is one of the cases above.
If you are working with a right angle triangle, you can get away with being given the hypotenuse and one of the sides. So you only need 2 facts. It is called the HL theorem. But that is a special case of SSS. The third side can be found from a^2 + b^2 = c^2.
You can also use the two sides making up the right angle but that is a special case of SAS.
Answer
There 6 parts to every triangle: 3 sides and 3 angles. If you show congruency, using any of the 3 facts above, you can conclude that the other 3 parts of the triangle are congruent as well as the three that you have.
Geometry is built on that wonderfully simple premise and it is your introduction to what makes a proof. So it's important that you understand how proving parts of congruent triangles work.
The answer is -2/6
Hope this helps
Maybe 400, but I’m not quite sure