One worker<span> produces an average of 84 units per </span>day<span> with a street </span>What is the probability<span> that in any </span>single day worker 1 will outproduce worker 2<span>? A) 0.1141.
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Answer, factory worker productivity<span> is </span>normally distributed<span>. </span>One worker produces<span> an </span>average<span> of 75 </span>units per day<span> with a standar, day with a </span>standard deviation<span> of 20. </span>Another worker produces<span> at an </span>average rate<span> of 65 </span><span>per day.
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Answer:
3x-1
Step-by-step explanation:
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Answer:
The correct option is C
Step-by-step explanation:
From the question we are told that
The number of independent variables is 
The number of observation is 
Since n is are independent variables then their degree of freedom is 3
The denominator(i.e z) degrees of freedom is evaluated as
So for the numerator (n) the degree of freedom is Df(n) = 3
So for the denominator(i.e z) the degree of freedom is Df(z) = 43
Answer:
1 hour and 15 minutes
Step-by-step explanation
There are 60 minutes in an hour. Add 15 minutes to get to 3:00 pm. From 3:00 pm to 4:00 pm is 1 hour. 15 minutes + 1 hour is 1 hour and 15 minutes
Hope this helps!
Answer:
60
Step-by-step explanation:
