Answer:
Algebra
Topics
How do you find the intercepts of x2y−x2+4y=0?
Algebra Graphs of Linear Equations and Functions Intercepts by Substitution
2 Answers
Gió
Mar 24, 2015
For the intercepts you set alternately x=0 and y=0 in your function:
and graphically:
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Alan P.
Mar 24, 2015
On the X-axis y=0
So
x2y−x2+4y=0
becomes
x2(0)−x2+4(0)=0
→−x2=0
→x=0
On the Y-axis x=0
and the original equation
x2y−x2+4y=0
becomes
(0)2y−(0)2+4y=0
→y=0
The only intercept for the given equation occurs at (0,0)
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It’s B dksmejnsjejwkwmwkwm
Second moment of area about an axis along any diameter in the plane of the cross section (i.e. x-x, y-y) is each equal to (1/4)pi r^4.
The second moment of area about the zz-axis (along the axis of the cylinder) is the sum of the two, namely (1/2)pi r^4.
The derivation is by integration of the following:
int int y^2 dA
over the area of the cross section, and can be found in any book on mechanics of materials.
The answer is 8 gram/cm^3
Hope this helps
Answer:
Step-by-step explanation:
Mean = ∑x/ N
91 = ∑x / 150
∑x = 150 * 91 = 13650
x= 6825 and y = 6825
