The last one are like terms because they can combine.
Given plane Π : f(x,y,z) = 4x+3y-z = -1
Need to find point P on Π that is closest to the origin O=(0,0,0).
Solution:
First step: check if O is on the plane Π : f(0,0,0)=0 ≠ -1 => O is not on Π
Next:
We know that the required point must lie on the normal vector <4,3,-1> passing through the origin, i.e.
P=(0,0,0)+k<4,3,-1> = (4k,3k,-k)
For P to lie on plane Π , it must satisfy
4(4k)+3(3k)-(-k)=-1
Solving for k
k=-1/26
=>
Point P is (4k,3k,-k) = (-4/26, -3/26, 1/26) = (-2/13, -3/26, 1/26)
because P is on the normal vector originating from the origin, and it satisfies the equation of plane Π
Answer: P(-2/13, -3/26, 1/26) is the point on Π closest to the origin.
Answer:5 million
Step-by-step explanation: Because 300 thousand is below 500 thousand so if its below 500 thousand it cant round up it rounds down.
Answer:
0.1349
Step-by-step explanation:
Given that:
Sample size, n = 500
20% of 500 ; 0.2 * 500 = 100
p = 0.18 ; n = 500 ; 1 - p = 0.82
P(x ≥ 100) ;
Using the binomial probability relation :
P(x =x) = nCx * p(x)^x * (1 - p)^(n - x
P(x ≥ 100) = 500C100 * 0.18^100 * 0.82^400
P(x ≥ 100) = 0.1349
