Question

Determine the number of real solutions of -2x^2+ 5x – 3 = 0. 2 1 (double root) 5 0

Answer 1

Answer:

${ \tt{ - 2 {x}^{2} + 5x - 3 = 0 }} \\ { \tt{2 {x}^{2} - 5x + 3 = 0}} \\ { \tt{(2x - 3)(x - 1) = 0}} \\ { \tt{x = \frac{3}{2} \: and \: 1}}$