2 years ago

Determine the number of real solutions of -2x^2+ 5x – 3 = 0. 2 1 (double root) 5 0

1 answer:

5 0

Answer:

${ \tt{ - 2 {x}^{2} + 5x - 3 = 0 }} \\ { \tt{2 {x}^{2} - 5x + 3 = 0}} \\ { \tt{(2x - 3)(x - 1) = 0}} \\ { \tt{x = \frac{3}{2} \: and \: 1}}$

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Does anyone know this?

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Answer:

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