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gavmur [86]
3 years ago
11

Write a c program to count the total number of commented characters and words in a c file taking both types of c file comments (

single line and block) into account.
Computers and Technology
2 answers:
Flura [38]3 years ago
4 0

Answer:

The C program for characters will be like the one below:

Explanation:

#include <stdio.h>

#include <stdlib.h>

int main()

{

   FILE * file;

   char path[100];

   char ch;

   int characters, words, lines;

   /* Input path of files to merge to third file */

   printf("Enter source file path: ");

   scanf("%s", path);

   /* Open source files in 'r' mode */

   file = fopen(path, "r");

   /* Check if file opened successfully */

   if (file == NULL)

   {

       printf("\nUnable to open file.\n");

       printf("Please check if file exists and you have read privilege.\n");

       exit(EXIT_FAILURE);

   }

   /*

    * Logic to count characters, words and lines.

    */

   characters = words = lines = 0;

   while ((ch = fgetc(file)) != EOF)

   {

       characters++;

       /* Check new line */

       if (ch == '\n' || ch == '\0')

           lines++;

       /* Check words */

       if (ch == ' ' || ch == '\t' || ch == '\n' || ch == '\0')

           words++;

   }

   /* Increment words and lines for last word */

   if (characters > 0)

   {

       words++;

       lines++;

   }

   /* Print file statistics */

   printf("\n");

   printf("Total characters = %d\n", characters);

   printf("Total words      = %d\n", words);

   printf("Total lines      = %d\n", lines);

   /* Close files to release resources */

   fclose(file);

   return 0;

}

Tanzania [10]3 years ago
3 0

#include<stdio.h>

#include<stdlib.h>

int comment1(FILE *fp)

{

   char ch;

   int count=0;

   while(fscanf(fp,"%c",&ch)!=EOF)

   {

       if(ch=='\n')

       {

           return count;

       }

       count++;

   }

   return count;

}

int comment2(FILE *fp)

{

   char ch;

   int count=0;

   while(fscanf(fp,"%c",&ch)!=EOF)

   {

       if(ch=='*')

       {

           fscanf(fp,"%c",&ch);

           if(ch=='/')

           {

               return count;

           }

           count++;

       }

       count++;

   }

   return 0;

}

int main()

{

   printf("Enter the file name:");

   char s[1000],ch,ch1;

   scanf("%s",s);

   FILE*fp;

   fp = fopen(s,"r");

   int count=0;

   while(fscanf(fp,"%c",&ch)!=EOF)

   {

       if(ch=='\"')

       {

           while(fscanf(fp,"%c",&ch)!=EOF)

           {

               if(ch=='\"')

               {

                   break;

               }

               if(ch=='\\')

               {

                   fscanf(fp,"%c",&ch);

               }

           }

       }

       else if(ch=='/')

       {

           fscanf(fp,"%c",&ch);

           if(ch=='/')

           {

               count += comment1(fp);

           }

           else if(ch=='*')

           {

               count += comment2(fp);

           }

       }

   }

   printf("%d\n",count);

   return 0;    

}

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Kay [80]

Answer:

  1. class AirConditioner:
  2.  def __init__(self, a_c=False):
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Explanation:

Firstly, create a class and name it as AirConditioner (Line 1).

Next in the class constructor, create the reference variable office_a_c (Line 3). Please note the reference variable shall be preceded with a self keyword. Besides, the reference variable is set to False by default.

Create an AirConditioner object (Line 6) and then use the dot syntax (.) to set the object reference variable office_a_c to True.

8 0
3 years ago
Write a function which sorts the queue in order from the smallest value to the largest value. This should be a modified version
PilotLPTM [1.2K]

Answer:

#include <iostream>

using namespace std;

void swap(int *a,int *b){    //function to interchange values of 2 variables

   int temp=*a;

   *a=*b;

   *b=temp;

}

void sort(int queue[],int n)

{

   int i,j;

   for(i=0;i<n;i++)      //to implement bubble sort

   {

       for(j=0;j<n-i-1;j++)

       {

           if(queue[j]>queue[j+1])

               swap(queue[j],queue[j+1]);    //to swap values of these 2 variables

       }

   }

}

int main()

{

   int queue[]={6,4,2,9,5,1};

   int n=sizeof(queue)/4;  //to find length of array

   sort(queue,n);

   for(int i=0;i<n;i++)

       cout<<queue[i]<<" ";

   return 0;

}

OUTPUT :

1 2 4 5 6 9

Explanation:

In the above code, Queue is implemented using an array and then passed to a function sort, so that the queue can be sorted in ascending order. In the sort function, in each pass 2 adjacent values are compared and if lower index value is greater than the higher one they are swapped using a swap function that is created to interchange the values of 2 variables.

7 0
3 years ago
List three functions that you can perform with a database that you cannot perform with a spreadsheet.
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5 0
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Consider a student club or organization in which you are a
lakkis [162]

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4 0
2 years ago
a transmitter is operating at 150 MHz with a power of 3 W into a one-quarter wavelength vertical antenna. The receiver, which is
Bogdan [553]

The received power will be 1.243 nW

We're given:

frequency f = 150MHz

distance of the receiver d = 32.2 km=32200m

Power of transmitter P_{t} = 3W

Antenna gain = 8dB

To find :

Power received P_{r}

P_{r}= \frac{P_{t} *G_{t}*G_{r}* \lambda^2 }{16*\pi^2*d^2}

where G_{t is transmit gain and G_{r is receive gain as refrenced to isotropic source

⇒wavelength \lambda = \frac{c}{f} where c is the speed of the light

⇒  \lambda = \frac{3*10^8}{150*10^6} =2m

G_{t}= 1*1.64 ( value of dipole = 1.64)

Now,

Antenna gain=8dB ( in decibals)

⇒10log(x)=8

⇒x=10^0^.^8=6.3095

⇒ considering isotropic receiver

⇒G_{r}=6.3095*1.64=10.3477 (dipole =1.64)

Now , using the formula

P_{r}= \frac{3 *1.64*10.3477 *2^2 }{16*\pi^2*32200^2}=1.2437*10^-^9

Hence The received power will be 1.243 nW

Leaen more about communication devices here:

brainly.com/question/14530107

#SPJ10

4 0
2 years ago
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