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ira [324]
3 years ago
12

What percentage is 15 out of 40

Mathematics
2 answers:
tatuchka [14]3 years ago
7 0

Answer:the answer would be 37.5


Step-by-step explanation: you can complete this by doing the following equation: 100 divided by 40, times 15.


irina1246 [14]3 years ago
5 0

Answer:

the answer is 6

Step-by-step explanation:

so you do 15 multiply by 40  and divide by 100

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A box has 6 beads of the same size, but all are different colors. Tania draws a bead randomly from the box, notes its color, and
kirill [66]

6 total beads

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1/6 of getting a yellow

1/6 of getting a blue and

1/6 of getting a yellow again

1/6 * 1/6 * 1/6 = 1/216 probability

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3 years ago
calculate the length of a piece of copper wire with a diameter of 2 mm and a resistance of 0.5omh. The resistivity value of this
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3 years ago
At Which values of x does the function f(x) have a vertical asymptote? Check all that apply
LUCKY_DIMON [66]

Answer:

C, D and E

Step-by-step explanation:

The denominator of f(x) cannot be zero as this would make f(x) undefined.

Equating the denominator to zero and solving gives the values that x cannot be and if the numerator is non zero for these values then they are vertical asymptotes.

solve 3x(x - 1)(x + 5) = 0

Equate each factor to zero and solve for x

3x = 0 ⇒ x = 0

x - 1 = 0 ⇒ x = 1

x + 5 = 0 ⇒ x = - 5

Vertical asymptotes at x = -5, x = 1 and x = 0

8 0
4 years ago
The sum of the first n terms of an arithmetic series is n/2(3n-5). If the second and fourth terms of the arithmetic series are t
sergiy2304 [10]

Let <em>a</em> be the first term in the arithmetic sequence. Since it's arithmetic, consecutive terms in the sequence differ by a constant <em>d</em>, so the sequence is

<em>a</em>, <em>a</em> + <em>d</em>, <em>a</em> + 2<em>d</em>, <em>a</em> + 3<em>d</em>, …

with the <em>n</em>-th term, <em>a</em> + (<em>n</em> - 1)<em>d</em>.

The sum of the first <em>n</em> terms of this sequence is given:

a + (a+d) + (a+2d) + \cdots + (a+(n-1)d) = \dfrac{n(3n-5)}2

We can simplify the left side as

\displaystyle \sum_{i=1}^n (a+(i-1)d) = (a-d)\sum_{i=1}^n1 + d\sum_{i=1}^ni = an+\dfrac{dn(n-1)}2

so that

an+\dfrac{dn(n-1)}2 = \dfrac{n(3n-5)}2

or

a+\dfrac{d(n-1)}2 = \dfrac{3n-5}2

Let <em>b</em> be the first term in the geometric sequence. Consecutive terms in this sequence are scaled by a fixed factor <em>r</em>, so the sequence is

<em>b</em>, <em>br</em>, <em>br</em> ², <em>br</em> ³, …

with <em>n</em>-th term <em>br</em> ⁿ⁻¹.

The second arithmetic term is equal to the second geometric term, and the fourth arithmetic term is equal to the third geometric term, so

\begin{cases}a+d = br \\\\ a+3d = br^2\end{cases}

and it follows that

\dfrac{br^2}{br} = r = \dfrac{a+3d}{a+d}

From the earlier result, we then have

n=7 \implies a+\dfrac{d(7-1)}2 = a+3d = \dfrac{3\cdot7-5}2 = 8

and

n=2 \implies a+\dfrac{d(2-1)}2 = a+d = \dfrac{3\cdot2-5}2 = \dfrac12

so that

r = \dfrac8{\frac12} = 16

and since the second arithmetic and geometric terms are both 1/2, this means that

br=16b=\dfrac12 \implies b = \dfrac1{32}

The sum of the first 11 terms of the geometric sequence is

<em>S</em> = <em>b</em> + <em>br</em> + <em>br</em> ² + … + <em>br</em> ¹⁰

Multiply both sides by <em>r</em> :

<em>rS</em> = <em>br</em> + <em>br</em> ² + <em>br</em> ³ + … + <em>br</em> ¹¹

Subtract this from <em>S</em>, then solve for <em>S</em> :

<em>S</em> - <em>rS</em> = <em>b</em> - <em>br</em> ¹¹

(1 - <em>r</em> ) <em>S</em> = <em>b</em> (1 - <em>r</em> ¹¹)

<em>S</em> = <em>b</em> (1 - <em>r</em> ¹¹) / (1 - <em>r</em> )

Plug in <em>b</em> = 1/32 and <em>r</em> = 1/2 to get the sum :

S = \dfrac1{32}\cdot\dfrac{1-\dfrac1{2^{11}}}{1-\dfrac12} = \boxed{\dfrac{2047}{32768}}

6 0
3 years ago
Is this true or false? Explain your thinking.<br> 4(5 +3) =(4 x 5) + (4 x 3)= 20 +12
ale4655 [162]

Answer:

<h2><u>True</u></h2>

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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