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yuradex [85]
3 years ago
15

Solve the quadratic equation 3x^2 +x-5=0 give your answers to two decimal places

Mathematics
1 answer:
ddd [48]3 years ago
8 0

Especially if we're to present the answers to 2 decimal places, we'd gues that the roots of this polynomial are not "nice."

My suggestion is that we use the quadratic formula to find the roots, and then write the associated factors.

In 3x^2 +x-5=0, a=3, b=1 and c= -5. Thus, the roots are

-1 plus or minus √(1^2 - 4(3)(-5) )

x = --------------------------------------------------

2(3)

or:

-1 plus or minus √61 -1 plus or minus 7.81

x = ----------------------------------- = ---------------------------------

6 6

Then one root is 6.81/6, or approx. 1.14, and the other is

-8.81/6, or approx. -1.47.

The solution set is then {-1.47, 1.14}.

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Solve x2 + 14x + 17 = –96 for x
jarptica [38.1K]

For this case we have to:

Given the quadratic equation of the form:

ax ^ 2 + bx + c = 0

The roots are given by:

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We can rewrite it in the following way:

x ^ 2 + 14x + 17 + 96 = 0\\x ^ 2 + 14x + 113 = 0

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a = 1\\b = 14\\c = 113

Where we have:

x = \frac {-14 \pm \sqrt {(14) ^ 2-4 (1) (113)}} {2 (1)}

x = \frac {-14 \pm \sqrt {(196-452)}} {2}

x = \frac {-14 \pm \sqrt {-256}} {2}

By definition: \sqrt {-1} = i

x = \frac {-14 \pm \sqrt {256} i} {2}

x = \frac {-14 \pm16i} {2}

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x = -7 \pm8i

Thus, the roots are given by imaginary numbers:

x_ {1} = - 7 + 8i\\x_ {2} = - 7-8i

Answer:

x_ {1} = - 7 + 8i\\x_ {2} = - 7-8i


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I hope that is correct and helps you! :)

Step-by-step explanation:

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