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katrin2010 [14]
3 years ago
7

Only the correct answer

Mathematics
1 answer:
storchak [24]3 years ago
6 0
Its A.........................................
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I REALLY NEED HELP ON THIS PLS HELP
Eva8 [605]

Part (a)

Answer: See the attached image below to see the filled out chart.

Note how rational and irrational numbers have nothing in common. This means there is no overlap. So they go in the rectangles. The two sets of numbers join up to form the entire set of real numbers.

Integers are in the set of rational numbers. This is because something like 7 is also 7/1; however 1/7 is not an integer. So not all rational numbers are integers. The larger purple circle is the set of integers.

The smaller blue circle is the set of whole numbers. The set of whole numbers is a subset of integers. Recall the set of whole numbers is {0,1,2,3,...} so we ignore the negative values only focusing on 0 and positive numbers that don't have any fractional values. In contrast, the set of integers is {..., -3, -2, -1, 0, 1, 2, 3, ...} here we do include the negatives.

============================================================

Part (b)

1) Some irrational numbers are integers.

This is false. An irrational number is not rational. The set of integers is contained entirely in the set of rational numbers.

---------------------------------

2) Some whole numbers are not irrational numbers.

This is false. The statement implies that some whole numbers are irrational, but the set of whole numbers is inside the set of rational numbers, which has no overlap with the irrationals. The statement should be "All whole numbers are not irrational numbers".

---------------------------------

3) All rational numbers are whole numbers.

This is false. A rational number like 1/3 is not a whole number.

---------------------------------

4) All integers are whole numbers

This is false. An integer like -44 is not a whole number because the set of whole numbers is {0,1,2,3,...} and we're not including negative values.

---------------------------------

In summary, all four statements for part (b) are false.

8 0
2 years ago
Read 2 more answers
A drink contains 20% cranberry juice and the rest is apple juice. What is the ratio of cranberry juice to apple juice? A.1:20 B.
yarga [219]
20% of the juice is cranberry
80% of the juice is apple
Our ratio would be 20:80
We can simplify it and it will become
1:4

So your answer would be B. 1:4

I hope this helps :)
6 0
3 years ago
600+600+200-200 Giving Brainliest​
Zigmanuir [339]
The final answer is 1,200
4 0
2 years ago
Read 2 more answers
According to Masterfoods, the company that manufactures M&M's, 12% of peanut M&M's are brown, 15% are yellow, 12% are re
Luda [366]

Answer:

The questions asked are

If you randomly select 4 peanuts

1. Compute the probability that exactly three of the four M&M’s are brown

2. Compute the probability that two or three of the four M&M’s are brown.

3. Compute the probability that at most three of the four M&M’s are brown.

4. Compute the probability that at least three of the four M&M’s are brown.

Step-by-step explanation:

Given the following information

Brown=12%. P(B)=0.12

Yellow=15%. P(Y)=0.15

Red=12%. P(R), =0.12

Blue=23%. P(B) =0.23

Orange, =23%. P(O) =0.23

Green=15%. P(G)=0.15

Question 1.

They are independent events

If there are exactly three brown and the last is not brown

P(B n B n B n B')

P(B)×P(B)×P(B)×P(B')

0.12×0.12×0.12×(1-P(B))

0.001728×(1-0.12)

0.001728×0.88

0.00152.

0.152%

2. If two or three are brown

I.e we are going to two brown and two none brown or three brown and one not brown. (P(B)×P(B)×P(B')×P(B'))+ (P(B)×P(B)×P(B'))

(0.12×0.12×0.88×0.88)+(0.12×0.12×0.12×0.88)

0.0112+0.00152

0.0127

1.27%

3. At most three brown out of four then we are going to have

BBBB', BBB'B', BB'B'B', B'B'B'B'

These are the cases of at most three brown.

P(B)×P(B)×P(B)×P(B') + P(B)×P(B)×P(B')×P(B') + P(B)×P(B')×P(B')×PB')+ P(B')×P(B')×P(B')×P(B')=

0.12×0.12×0.12×0.88+ 0.12×0.12×0.88×0.88+ 0.12×0.88×0.88×0.88+ 0.88×0.88×0.88×0.88=0.694

0.694

69.4%

4. At least 3 brown out of four selection

I.e BBBB', BBBB

These are the two options

P(B)×P(B)×P(B)×P(B') + P(B)×P(B)×P(B)×P(B)=

0.12×0.12×0.12×0.88 + 0.12×0.12×0.12×0.12

0.001728

0.173%

4 0
3 years ago
Read 2 more answers
!30 POINTS! How can I use this trapezoid to prove the Pythagorean Theorem?
stiks02 [169]

Answer:

Pythagorean Theorem: c2 = a2 + b2

Find the area by adding the areas of the three triangles. The area of a right triangle is: A = ½bh

Two triangles are identical so you can just multiply the area of the first triangle by two: 2A1 = 2(½bh) = 2(½ab) = ab.

The total area of the trapezoid is : A1 + A2 = ab + ½c2

You multiply both sides by 2 to get rid of the ½: (a2 + 2ab + b2) = 2ab + c2

You subtract out the 2ab: a2 + b2 = c2.

Then what is left is the proof: a2 + b2 = c2

6 0
2 years ago
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