The third one it could be one.
Area of the shaded part is given by:
A=(area of the sector)-(area of triangle)
A=(θ/360πr²)-(1/2sinθab)
A=(120/360*π*6²)-(0.5*6²*sin120)
A=12π-15.59
A=22.1 cm²
Answer: A=22.1 cm²
25(6) + [8(6-s)] = t, where s = number of hours and t = total.
