Design a 16K x 8 memory using the following ICs:
1 answer:
Answer:
Required memory size is 16k x 8
16k = 24 x 210 = 214
Hence, No. of address lines = 14
No. of data lines = 8
a) Size of IC 1024 x 1
Total number of ICs required = 16k x 8 / 1024 x 1 = 16 x 8 = 128
b) Size of IC 2k x 4
Total number of ICs required = 16k x 8 / 2k x 4 = 8 x 2 = 16
c) Size of IC 1k x 8
Total number of ICs required = 16k x 8 / 1k x 8 = 16 x 1 = 16
Explanation:
For a, 10 address lines from A0 to A9 are used to select any one of the memory location out of 1024 memory locations present in a IC.
For b, 11 address lines from A0 to A10 are used to select any one of the memory location out of 2k=2048 memory locations present in a IC.
For c, 10 address lines from A0 to A9 are used to select any one of the memory location out of 1k=1024 memory locations present in a IC.
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Answer:
The algorithm:
Input days
sum = 0
for i = 1 to
input text
sum = sum + text
end for
average = sum/days
print average
The program in pascal:
var days, sum, text, i:integer;
var average : real;
Begin
write ('Days: '); readln(days);
sum:=0;
for i := 1 to do
write ('Text: '); readln(text);
sum:=sum+text;
end;
average := (sum/days);
writeln ('The average text is' , average);
End.
Explanation:
This declares all variables
var days, sum, text, i:integer;
var average : real;
This begins the program
Begin
This gets the number of days from the user
write ('Days: '); readln(days);
Initialize sum to 0
sum:=0;
This iterates through the days
for i := 1 to do begin
This gets the text for each day
write ('Text: '); readln(text);
This sums up the texts
sum:=sum+text;
End loop
end;
Calculate average
average := (sum/days);
Print average
writeln ('The average text is' , average);
End program
End.