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3 years ago

The wheels on the golf cart on Fortnite are 12 feet in diameter how many feet around is one of the tires

Mathematics

2 answers:

emmainna [20.7K]3 years ago

5 0

Answer:

37.7 feet

Step-by-step explanation:

circumference=πd

3.14x12=

37.7

IrinaVladis [17]3 years ago

4 0

Answer:

37.68 feet

Step-by-step explanation:

Circumference equation:

$C=\pi d$

Plug in the diameter and solve:

$C=(3.14)(12)$

$C=37.68$

37.68 feet

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Step-by-step explanation:

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3 years ago

What is the mean absolute deviation for the set of data below?<br><br> 2, 8, 10, 16

Evgesh-ka [11]

Solution: We are given below data:

$2, 8, 10, 16$

Now to find the mean deviation, we use the below formula:

$MD= \frac{\sum|X-\bar{X}|}{N}$

Where:

$\sum,$ represents the summation

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N represents the number of observation.

$\bar{X}= \frac{\sum{X}}{N}= \frac{2+8+10+16}{4}=9$

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Therefore, the mean deviation is:

$MD= \frac{16}{4}$

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3 years ago

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A class of 30 students has 12 girls. What is the ratio to boys?

miv72 [106K]

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Show that d^2y/dx^2=-2x/y^5, if x^3 + y^3=1

aalyn [17]

Answer:

y³ + x³ = 1

First, differentiate the first time, term by term:

${3y^{2}.\frac{dy}{dx} + 3x^{2}} = 0 \\\\{3y^{2}.\frac{dy}{dx} = -3x^{2}} \\\\\frac{dy}{dx} = \frac{-3x^{2}}{3y^{2}} \\\\\frac{dy}{dx} = \frac{-x^{2}}{y^{2}}$

↑ we'll substitute this later (4th step onwards)

Differentiate the second time:

$3y^{2}.\frac{dy}{dx} + 3x^{2} = 0 \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{dy}{dx})^{2} + 6x = 0 \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{dy}{dx})^{2} = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{-x^{2} }{y^{2} })^{2} = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{x^{4} }{y^{4} }) = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + \frac{6x^{4} }{y^{3} } = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} = - 6x - \frac{6x^{4} }{y^{3} } \\\\$

$3y^{2}.\frac{d^{2} y}{dx^{2}} = - \frac{- 6xy^{3} - 6x^{4} }{y^{3}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{- 6xy^{3} - 6x^{4} }{3y^{2}. y^{3}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{- 2xy^{3} - 2x^{4} }{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x (y^{3} + x^{3})}{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x (1)}{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x}{y^{5}}$

3 0

3 years ago