Yes 0.634 is a rational
number.
Rational numbers are those numbers that can be still expressed in
standard form or in fraction form and vice-versa. Unlike irrational numbers
that are opposed to the definition of rational numbers. These values include
pi, square root of two and etc. These values are impossible to fractionize.
To better illustrate this
circumstance.
We can have calculate a number that will have a quotient of 0.634
or a fraction that is equal to the given value.
<span><span>
1. </span><span> 634/1000 =
0.634</span></span>
<span><span>2. </span><span> 317/500 = 0.634
</span></span>
Answer:
![\frac{\sqrt[3]{16y^4}}{x^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B16y%5E4%7D%7D%7Bx%5E2%7D)
Step-by-step explanation:
The options are missing; However, I'll simplify the given expression.
Given
![\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B32x%5E3y%5E6%7D%7D%7B%5Csqrt%5B3%5D%7B2x%5E9y%5E2%7D%20%7D)
Required
Write Equivalent Expression
To solve this expression, we'll make use of laws of indices throughout.
From laws of indices ![\sqrt[n]{a} = a^{\frac{1}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%7D%20%20%3D%20a%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D)
So,
gives

Also from laws of indices

So, the above expression can be further simplified to

Multiply the exponents gives

Substitute
for 32


From laws of indices

This law can be applied to the expression above;
becomes

Solve exponents


From laws of indices,
; So,
gives

The expression at the numerator can be combined to give

Lastly, From laws of indices,
; So,
becomes
![\frac{\sqrt[3]{(2y)}^{4}}{x^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B%282y%29%7D%5E%7B4%7D%7D%7Bx%5E2%7D)
![\frac{\sqrt[3]{16y^4}}{x^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B16y%5E4%7D%7D%7Bx%5E2%7D)
Hence,
is equivalent to ![\frac{\sqrt[3]{16y^4}}{x^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B16y%5E4%7D%7D%7Bx%5E2%7D)
Float
because the water weighs more so it will hold it.
Answer:
t = 4
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define equation</u>
t + t + t = 12
<u>Step 2: Solve for </u><em><u>t</u></em>
- Combine like terms (t): 3t = 12
- Divide 3 on both sides: t = 4
<u>Step 3: Check</u>
<em>Plug in t into the original equation to verify it's a solution.</em>
- Substitute in <em>t</em>: 4 + 4 + 4 = 12
- Add: 8 + 4 = 12
- Add: 12 = 12
Here we see that 12 does indeed equal 12.
∴ t = 4 is a solution of the equation.