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Ksju [112]
3 years ago
15

For quadrilateral ABCD, determine the most precise name for it. A(-2,3), B (9,3), C(5,6) and D(2,6). Show your work and explain.

Mathematics
1 answer:
Andrews [41]3 years ago
7 0

I graphed the 4 points and connected the dots. (Sorry I'm not able to show this)

I then realized it was some type of trapezoid however, I wasn't sure which kind of trapezoid (regular or isosceles) so I googled the properties of both and concluded that it makes a regular trapezoid.

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What is the equation of the line represented by the table below? Х-2,-1,0,1,2 y16,11,6,1,-4
pashok25 [27]

Answer:

y = -5x + 6

Step-by-step explanation:

General equation of a line : y = mx + c......where c is intercept

To find m pick any two points..

(-2, 16) and (-1, 11)

Using (y - y¹) / (x - x¹)

(11 - 16) / (-1 - [-2]) = -5 / 1

= -5

To find c sub with any point for (x, y) and m

using (2, -4)

y = mx + c

-4 = -5(2) + c

-4 = -10 + c

6 = c

Input the values of m and c in the general equation without x and y

; y = -5x + 6

5 0
3 years ago
Can you guys please help me? I understand everything but the last step.​
MariettaO [177]

Answer:

It is because you have to get rid of the power of 2 from c. In order to get rid, you have to square root it on both sides :

c² = 74

√(c²) = √74

c^(1/2×2) = √74

c = √74

Using Indices formula, (a^m)^n = a^(mn)

8 0
3 years ago
If triangle ABC A(-4,5) B(-4,-6) and C(3,-8)is rotated 90 degrees counterclockwise about the origin, what would be the coordinat
stepladder [879]
(-4,-5)(-4,6)(3,8)
all y signs become opposite!:)
5 0
3 years ago
Read 2 more answers
Express in decimal numerals.- nine and two hundred thirty-five thousands
AleksandrR [38]
Well the question is not so clear put I will give it a try 
9,235,000
I am pretty sure that's how you write it 
5 0
3 years ago
Read 2 more answers
Find the Area of the shaded part.
Westkost [7]

To find the area of the shaded part we have to subtract the rectangle area from the triangle area :

s =  \frac{1}{2}  \times (8x + 2)(6x) - (x)(3x + 1) \\

s =  \frac{1}{2}  \times (48 {x}^{2}  + 12x) - (3 {x}^{2}  + x) \\

s =  \frac{48}{2}  {x}^{2}  +  \frac{12}{2} x - 3 {x}^{2}  - x \\

s = 24 {x}^{2}  + 6x - 3 {x}^{2}  - x

s = 24 {x}^{2}  - 3 {x}^{2}  + 6x - x

s = 21 {x}^{2}  + 5x

And we're done

Have a great day ♡

4 0
2 years ago
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