3 years ago

5tanx-2cotx+1=0...... .

Mathematics

1 answer:

Verdich [7]3 years ago

7 0

Step-by-step explanation:

5(tanx)^2 -2 +tanx=0

let tanx=y

5y^2 + y-2=0

y=0.5403 or y= -0.7403

tanx=0.5403

x=arctan(0.5403)

x=28.38°

tanx=-0.7403

x=arctan(-0.7403)

x=143.49°

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