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olchik [2.2K]
3 years ago
5

5tanx-2cotx+1=0...... .

Mathematics
1 answer:
Verdich [7]3 years ago
7 0

Step-by-step explanation:

5(tanx)^2 -2 +tanx=0

let tanx=y

5y^2 + y-2=0

y=0.5403 or y= -0.7403

tanx=0.5403

x=arctan(0.5403)

x=28.38°

or

tanx=-0.7403

x=arctan(-0.7403)

x=143.49°

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Solve the logarithmic equation. Be sure to reject any value of log (X + 8) = log x + log 8​
swat32

Answer:

x = 8/7

Step-by-step explanation:

log (X + 8) = log x + log 8​

We know that log a + log b = log ab

log (X + 8) = log 8x

Raise each side to base 10

10^log (X + 8) = 10^log 8x

x+8 = 8x

Subtract x from each side​

x+8-x = 8x-x

8 = 7x

Divide by 7

8/7 = 7x/7

8/7 =x

6 0
3 years ago
Read 2 more answers
The radioactive isotope radium has a half-life of 1,600 years. The mass of a 100-gram sample of radium will be______ grams after
Olenka [21]
To solve this we are going to use the half life equation N(t)=N_{0} e^{( \frac{-0.693t}{t _{1/2} }) }
Where:
N_{0} is the initial sample
t is the time in years
t_{1/2} is the half life of the substance
N(t) is the remainder quantity after t years 

From the problem we know that:
N_{0} =100
t=200
t_{1/2} =1600

Lets replace those values in our equation to find N(t):
N(200) =100e^{( \frac{(-0.693)(200)}{1600}) }
N(200)=100e^{( \frac{-138.6}{1600} )}
N(200)=100e^{-0.086625}
N(200)=91.7

We can conclude that after 1600 years of radioactive decay, the mass of the 100-gram sample will be 91.7 grams.

8 0
3 years ago
PLEASE HELP AND FAST!!!!!!!! WITH STEPS PLEASE
BaLLatris [955]

Answer:

Step-by-step explanation:

5c+1+3c=61

8c+1=61

8c=62

c=7.75

4 0
3 years ago
A local animal shelter has 27 dogs and 23 cats. What percent of the<br> animals are dogs?
SVEN [57.7K]

Answer:

54%

Step-by-step explanation:

total  animals=27+23=50

dogs=\frac{27}{50} \times100=54

6 0
3 years ago
-7 \times (7 + 9)−7×(7+9)
prisoha [69]

Answer:

−224

Step-by-step explanation:

−7(7+9)−7(7+9)

=(−7)(16)−7(7+9)

=−112−7(7+9)

=−112−(7)(16)

=−112−112

=−224

8 0
3 years ago
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