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Ray Of Light [21]
3 years ago
10

On a position-versus-time graph, where is time usually shown?

Chemistry
2 answers:
Ivahew [28]3 years ago
6 0

Answer:

On a position-versus-time graph,<u><em> along the x-axis (option b)</em></u> is time usually shown.

Explanation:

One way to describe and study the movements is by means of graphs that represent distance-time (distance as a function of time), speed-time (speed as a function of time) and acceleration-time (acceleration as a function of time).

Then, as the displacements are made while time passes, the description of the movement is facilitated by making a graph of position versus time. In the vertical axis the positions that the body occupies are usually represented and in the horizontal axis the time. Similarly, velocity or acceleration can be represented versus time, where the horizontal axis is time and the vertical axis is velocity or acceleration.

Taking into account that the horizontal axis belongs to the x axis and the vertical axis to the y axis:

<u><em>On a position-versus-time graph, along the x-axis (option b) is time usually shown.</em></u>

Dennis_Churaev [7]3 years ago
5 0

time is usually on the x axis while position is on the y axis>

hope this helped ^_^

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If an individual proton has mass 1.007825 amu, and an individual neutron has mass 1.008665 amu, what's the calculated mass of a
german

Answer:

C) 237.96682 amu

Explanation:

The symbol for neptunium-236 is given as;

²³⁶₉₃Np

This element has 93 protons and (236 - 93 = 143) neutrons.

Mass Number =Total mass of Protons + Total mass of neutrons

Total Mass pf protons = 93 * 1.007825 amu, = 93.727725 amu

Total mass of Neutrons = 143 * 1.008665 amu = 144.239095 amu

Mass = 144.239095 + 93.727725  = 237.96682 amu

Correct option is option C.

7 0
3 years ago
Which postulate of Dalton's atomic model was later changed and why?
telo118 [61]

Answer:

Explanation:

Part two of Dalton's theory had to be modified after mass spectrometry experiments demonstrated that atoms of the same element can have different masses because the number of neutrons can vary for different isotopes of the same element. ... Scientists have even developed the technology to see the world on an atomic level!

hoped i helped you :)

4 0
3 years ago
How many kilometers can the car travel on the amount of gasoline that would fit in a soda can? The volume of a soda can is 355 m
g100num [7]
I'll assume that the car is a Honda Insight with <span>EPA gas mileage rating of 57mi/gal in the city.

First, we will convert all units into Km and mL:
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Then, we will calculate the distance the car can move by multiplying the mileage rating and the the volume available as follows (note that I will be converting units in the same step):
distance = <span>(57mi/gal) x (1.609344 km/1mi) x (1gal/3785.411mL) x 355mL 
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4 0
4 years ago
Read 2 more answers
In which reaction does the oxidation number of hydrogen change? In which reaction does the oxidation number of hydrogen change?
dedylja [7]

<u>Answer:</u> The correct answer is 2Na(s)+2H_2O(l)\rightarrow 2NaOH(aq.)+H_2(g)

<u>Explanation:</u>

Oxidation number is defined as the number which is given to an atom when it looses or gains electron. When an atom looses electron, it attains a positive oxidation state. When an atom gains electron, it attains a negative oxidation state.

Oxidation state of the atoms in their elemental state is considered as 0. Hydrogen is present as gaseous state.

For the given chemical reactions:

  • <u>Reaction 1:</u>  2HClO_4(aq.)+CaCO_3(s)\rightarrow Ca(ClO_4)_2(aq.)+H_2O(l)+CO_2 (g)

Oxidation state of hydrogen on reactant side: +1

Oxidation state of hydrogen on product side: +1

Thus, the oxidation state of hydrogen is not changing.

  • <u>Reaction 2:</u>  CaO(s)+H_2O(l)\rightarrow Ca(OH)_2(s)

Oxidation state of hydrogen on reactant side: +1

Oxidation state of hydrogen on product side: +1

Thus, the oxidation state of hydrogen is not changing.

  • <u>Reaction 3:</u>  HCl(aq.)+NaOH(aq.)\rightarrow NaCl(aq.)+H_2O(l)

Oxidation state of hydrogen on reactant side: +1

Oxidation state of hydrogen on product side: +1

Thus, the oxidation state of hydrogen is not changing.

  • <u>Reaction 4:</u>  2Na(s)+2H_2O(l)\rightarrow 2NaOH(aq.)+H_2(g)

Oxidation state of hydrogen on reactant side: +1

Oxidation state of hydrogen on product side: 0

Thus, the oxidation state of hydrogen is changing.

  • <u>Reaction 5:</u>  SO_2(g)+H_2O(l)\rightarrow H_2SO_3(aq.)

Oxidation state of hydrogen on reactant side: +1

Oxidation state of hydrogen on product side: +1

Thus, the oxidation state of hydrogen is not changing.

Hence, the correct answer is 2Na(s)+2H_2O(l)\rightarrow 2NaOH(aq.)+H_2(g)

6 0
3 years ago
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iren2701 [21]
Can you restate the questions again ?
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