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3 years ago

There is an error in the rate-determining step of the following proposed mechanism.

Chemistry

1 answer:

yulyashka [42]3 years ago

5 0

Answer:

The steps with correct mechanism are given below:

1) CH₄(g) + Cl(g) → CH₃(g) + HCl(g) : This is a slow step.

The rate is given as: R1 = k₁[CH₄][Cl]

2) CH₃(g) + Cl₂(g) → CH₃Cl(g) + Cl(g): This is a fast step.

The rate is given as: Rate = k₂[CH₃][Cl₂]

∴ CH₄(g) + Cl₂(g) → CH₃Cl(g) + HCl(g)

Here, the slowest step will be the rate-determining step.

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Hydrocarbons contain only _____. carbon and hydrogen carbon, hydrogen, and oxygen carbon and nitrogen carbon and helium

Sati [7]

Hydrocarbons contain only Carbon and hydrogen.

Hope this helps!

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3 years ago

Read 2 more answers

The two isotopes of chlorine are 3517Cl and 3717Cl. Which isotope is the most abundant?

nikklg [1K]

Answer:

The most abundant isotope is ³⁵Cl₁₇.

Since the average atomic mass of Cl is 35.45 g/mole, so the most abundant one is that one near this number, ³⁵Cl₁₇.

³⁵Cl₁₇ is found by 75 % and ³⁷Cl₁₇ is found by 25 % by a ratio 3:1.

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3 years ago

Consider the electrolysis of molten barium chloride, BaCl2. (a) Write the half-reactions. (b) How many grams of barium metal can

Zielflug [23.3K]

Answer: a) Cathode(-): $Ba^+^2+2e^-\rightarrow Ba$

Anode(+): $2Cl^-\rightarrow Cl_2+2e^-$

b) 0.640 grams of Ba will be deposited.

Explanation: a) The problem is based on Faraday law of electrolysis. Molten barium chloride has $Ba^+^2$ ion and $Cl^-$ ion. Barium ion is reduced and chloride is oxidized. Reduction takes place at cathode and oxidation at anode. So, the half reactions will be:

Cathode(-): $Ba^+^2+2e^-\rightarrow Ba$

Anode(+): $2Cl^-\rightarrow Cl_2+2e^-$

b) The question asks, how many grams of barium metal can be produced by supplying 0.50 ampere for 30 minutes.

From the Cathode half-reaction, 1 mole of Ba is deposited by 2 moles of electrons and we know that 1 mole of electron carries one Faraday that is 96485 Coulomb.

Coulombs for 2 moles of electrons will be = 2*96485 C = 192970 C

So, we can say that, 192970 C will deposit 1 mole of Ba metal.

Total available coulombs can be calculated using the formula:

q=i*t

where, q is electric charge in coulomb, i is current in ampere and t is time in seconds.

$q=q=0.50A*30min(\frac{60sec}{1min})$

q = 900 C (note: 1 C = 1 A*sec)

Let's calculate how many moles of Ba will get deposited by 900 C.

$900C(\frac{1molBa}{192970C})$

= 0.00466 mole Ba

Convert the moles of Ba to grams and for this we multiply by molar mass of Ba which is 137.33 gram per mol.

$0.00466molBa(\frac{137.33g}{1mol})$

= 0.640 g Ba

So, 0.50 A for 30 minutes will deposit 0.640 grams of Ba metal.

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2 years ago

A 50.0 mL solution of 0.133 M KOH is titrated with 0.266 M HCl . Calculate the pH of the solution after the addition of each of

shtirl [24]

Answer:Calculate The PH Of The Solution After The Addition Of The Following Amounts Of HCl. PLEASE HELP! SHOW ALL STEPS!! This problem has been solved!

Explanation:

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2 years ago

With white light, a team measured a 0.7% percent change with 3.5g of plant matter in a one liter container. Convert

Strike441 [17]

moles CO₂ = 5.57.10⁻⁴

<h3>Further explanation </h3>

A mole is a number of particles(atoms, molecules, ions) in a substance

Can be formulated :

$\tt mol=\dfrac{mass}{MW}$