Answer: 50%
Explanation:
The number of electron pairs are 2 for hybridization to be 
and the electronic geometry of the molecule will be linear.
1. percentage of s character in sp hybrid orbital =
2. percentage of s character in 
hybrid orbital =
3. percentage of s character in 
hybrid orbital =
Thus percentage of s-character in an sp hybrid is 50%.
The Solar System[b] is the gravitationally bound system of the Sun and the objects that orbit it, either directly or indirectly.[c] Of the objects that orbit the Sun directly, the largest are the eight planets,[d] with the remainder being smaller objects, the dwarf planets and small Solar System bodies. Of the objects that orbit the Sun indirectly—the natural satellites—two are larger than the smallest planet, Mercury.[e]
Answer:
Weigh the empty crucible, and then weigh into it between 2 g and 3 g of hydrated copper(II) sulphate. Record all weighings accurate to the nearest 0.01 g.
Support the crucible securely in the pipe-clay triangle on the tripod over the Bunsen burner.
Heat the crucible and contents, gently at first, over a medium Bunsen flame, so that the water of crystallisation is driven off steadily. The blue colour of the hydrated compound should gradually fade to the greyish-white of anhydrous copper(II) sulfate. Avoid over-heating, which may cause further decomposition, and stop heating immediately if the colour starts to blacken. If over-heated, toxic or corrosive fumes may be evolved. A total heating time of about 10 minutes should be enough.
Allow the crucible and contents to cool. The tongs may be used to move the hot crucible from the hot pipe-clay triangle onto the heat resistant mat where it should cool more rapidly.
Re-weigh the crucible and contents once cold.
Calculation:
Calculate the molar masses of H2O and CuSO4 (Relative atomic masses: H=1, O=16, S=32, Cu=64)
Calculate the mass of water driven off, and the mass of anhydrous copper(II) sulfate formed in your experiment
Calculate the number of moles of anhydrous copper(II) sulfate formed
Calculate the number of moles of water driven off
Calculate how many moles of water would have been driven off if 1 mole of anhydrous copper(II) sulfate had been formed
Write down the formula for hydrated copper(II) sulfate.
#*#*SHOW FULLSCREEN*#*#
Explanation:
Answer:
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Explanation:
fdddddddddddddddddddddddddd
First, find the total mass.
34.5 g + 18.2 g + 2.6 g = 55.3 g
Divide the mass of each element by total mass.
34.5 g / 55.3 g = .62 x 100 = 62% element a
18.2 g / 55.3 = .33 x 100 = 33% element b
2.6 g / 55.3 = .047 x 100 = 4.7% element c
Hope I helped!
