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NISA [10]
3 years ago
13

Which shows the domain range of these function?

Mathematics
2 answers:
Bas_tet [7]3 years ago
7 0

Answer: domain: (-oo,oo) range: (0,oo)

Step-by-step explanation:

Nadya [2.5K]3 years ago
6 0

Answer:

Answer: domain: (-oo,oo) range: (0,oo)

Step-by-step explanation:

just did the test

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tia_tia [17]

Answer:

aakkakjasjsbsvshsjsbsbanjasjsjj

5 0
2 years ago
When the exponent blank is applied to a nonzero base, the result is always 1
Anestetic [448]

0

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2 years ago
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Worth 12 Points, i spent 24
rewona [7]

Answer:

  \displaystyle m^{\frac{35}{12}}n^{-\frac{28}{15}}=\frac{m^{\frac{35}{12}}}{n^{\frac{28}{15}}}

Step-by-step explanation:

The relevant rule of exponents is ...

  (a^b·c^d)^e = a^(be)·c^(de)

Then ...

  (m^(5/4)·n^(-4/5))^(7/3) = m^(5/4·7/3)·n^(-4/5·7/3)

  = m^(35/12)·n^(-28/15)

__

Since you want positive rational exponents, you can write this as ...

  = m^(35/12)/n^(28/15)

6 0
3 years ago
Maria used a number line to find 12 ÷ 4.
aleksandrvk [35]

Answer:

12 divided by 4 is 3, this is how::

Step-by-step explanation:

            ------ .(-4)------- .(-4) ---------.(-4)

<---------------------------------------------------->

0  1  2  3  4  5  6  7  8  9  10  11  12

hope this made sense

8 0
3 years ago
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Use the dot product to determine whether the vectors are parallel, orthogonal, or neither. v = (sqrt)2j, w = 4i
svetoff [14.1K]
Hello,

As \vec{i}*\vec{j}=0\\&#10;\vec{v}*\vec{w}=\sqrt{2}*\vec{i}*4*\vec{j}=4*\sqrt{2}*0=0
Vectors are orthogonal.
4 0
3 years ago
Read 2 more answers
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