Can you answer the question for me? And no buggin cause I da need help

What is the scale factor of triangle ABC to triangle DEF?

8_murik_8 [283]

Answer:

Second option, scale factor is 2.5

Step-by-step explanation:

We see that ∠B ≅ ∠E and ∠C ≅ ∠F, therefore, ΔABC ~ ΔDEF by the AA Similarity for Triangles Theorem which states that if two pairs of corresponding angles are congruent in two triangles, then those two triangles are similar. To find the scale factor, all we have to do is DF / AC = 5/2 or 2.5.

5 0

3 years ago

A large container holds 8 gallons of water. It begins leaking at a constant rate. After 48 minutes, the container has 5 gallons

Gelneren [198K]

Whats the question?????????

5 0

3 years ago

What is 100/20and 54/7

Deffense [45]

Answer:

they are improper fractions

5 0

2 years ago

$500 are deposited into an account semiannuallysemiannually for six years at an interest rate of 7.2% compounded semiannually.

kobusy [5.1K]

Each year 107.2%increase of budget
first year 500 * 1.072 = 536
second year 536 * 1.072 = 574.592
third year 574.592 * 1.072 = 615.962624
..
..
sixth year 707.854392 * 1.072 = 758.819908

or you can just (1.072)^6 * 500 = 1.517639816659862 * 500 = 758.8199083299308

bingo........

8 0

3 years ago

Read 2 more answers

In 2008, the average household debt service ratio for homeowners was 13.2. The household debt service ratio is the ratio of debt

ankoles [38]

Answer:

$t=\frac{13.88-13.2}{\frac{3.14}{\sqrt{44}}}=1.436$

$df=n-1=44-1=43$

$p_v =P(t_{(43)}>1.436)=0.079$

We see that the p value i higher than the significance level so then we FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly higher than 13.2 *the value of 2008 ).

Step-by-step explanation:

Information given

$\bar X=13.88$ represent the sample mean

$s=3.14$ represent the sample standard deviation

$n=44$ sample size

$\mu_o =13.2$ represent the value that we want to test

$\alpha=0.05$ represent the significance level

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test

Hypothesis to test

We want to conduct a hypothesis in order to check if the true mean has increased from 2008 , and the system of hypothesi are:

Null hypothesis: $\mu \leq 13.2$

Alternative hypothesis: $\mu > 13.2$

The statistic for this case is:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Calculating the statistic

Replacing the info given we got:

$t=\frac{13.88-13.2}{\frac{3.14}{\sqrt{44}}}=1.436$

P-value

The degrees of freedom are:

$df=n-1=44-1=43$

Since is a right tailed test the p value is:

$p_v =P(t_{(43)}>1.436)=0.079$

Decision

We see that the p value i higher than the significance level so then we FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly higher than 13.2 *the value of 2008 ).

8 0

3 years ago