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tangare [24]
3 years ago
12

which unit would you use to measure the volume of a small cardboard box a cubic centimeters b grams c degrees d liters

Mathematics
2 answers:
MatroZZZ [7]3 years ago
8 0
Degrees measures temperature,
liters measures liquids,
grams measures mass, 
cubic centimeters measures volume.
kogti [31]3 years ago
7 0

Answer:

A:Cubic centimeters

Step-by-step explanation:

We are given that some units

We have to find that which unit you would use to measure the volume of box.

We know that  when side of cardboard box is given in meters then S.I unit of volume of box=cubic meters.

When side of box is given in cm then the S.I unit of volume is cubic centimeters.

When a substance is liquid

Then , volume of liquid is measured in litres or mL.

Gram is a unit of volume

Degrees is unit of temperature.

Hence, small cardboard box is solid then its volume can be measure in cubic centimeters

Therefore, option A is true.

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Which linear function represents the line given by the point-slope equation y + 7 = -2/3 (x + 6)?
PolarNik [594]
Got this from someone else but it answers your question

O f(x) = -x-1
Step-by-step explanation:
We want to isolate the 'y' variable, so we will subtract 7 from both sides.
y = x + 6 - 7
y = x -1

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6 0
2 years ago
Question
meriva

Question:

In a neighbourhood pet show, each of the animals entered is equally likely to win. if there are 7 dogs, 6 cats, 3 birds, and 2 gerbils entered, what is the probability that a bird will win the top prize?

Answer:

Probability that a bird will win the top prize is 0.167

Step-by-step explanation:

Given:

The number of  dogs  = 7

The number of  cats = 6

The number of  birds  = 3

The number of gerbils = 2

To Find:

Probability that a bird will win the top prize = ?

Solution:

Let us first find the total number of  pets .

The Total number of pets = 7 + 6 + 3  + 2 =  18

Now the probability of  a bird will win the top prize is

=> \frac{\text {Number of birds}}{\text{ Total number of pets}}

=>\frac{3}{18}

=> \frac{1}{6}

=>0.167

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3 years ago
Label each triangle
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Answer: Top right and left are ACUTE, Bottom right is RIGHT, and bottom left is OBTUSE.

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What is 0+0? (i obviously know it but its to give out points.)
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Answer:

0

Step-by-step explanation:

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6 0
3 years ago
Let the random variable X be the number of rooms in a randomly chosen owner-occupied housing unit in a certain city. The distrib
natali 33 [55]

Answer:

a) X is a discrete random variable.

b) 2% probability of choosing a unit with 10 rooms

c) 98% probability that a unit chosen at random is not a 10-room unit

d) 30% probability that a unit chosen at random has less than five rooms

e) 7% probability that a unit chosen at random has less than five rooms

Step-by-step explanation:

The distribution means that:

7% probability that a randomly chosen owner-occupied housing unit in a certain city has 3 rooms.

23% probability that a randomly chosen owner-occupied housing unit in a certain city has 4 rooms.

36% probability that a randomly chosen owner-occupied housing unit in a certain city has 5 rooms.

19% probability that a randomly chosen owner-occupied housing unit in a certain city has 6 rooms.

5% probability that a randomly chosen owner-occupied housing unit in a certain city has 7 rooms.

5% probability that a randomly chosen owner-occupied housing unit in a certain city has 8 rooms.

3% probability that a randomly chosen owner-occupied housing unit in a certain city has 9 rooms.

?% probability that a randomly chosen owner-occupied housing unit in a certain city has 10 rooms.

(a) Is X a discrete or continuous random variable?

X is the number of rooms in a randomly selected house. The number of rooms is a countable variable, that is, only assumes values like 1,2,3,4,... You cannot have 3.5 rooms, for example.

So X is a discrete random variable.

(b) What must be the probability of choosing a unit with 10 rooms?

The sum of all probabilities must be 100%(1 decimal). So

0.07 + 0.23 + 0.36 + 0.19 + 0.05 + 0.05 + 0.03 + ? = 1

0.98 + ? = 1

? = 0.02

2% probability of choosing a unit with 10 rooms

(c) What is the probability that a unit chosen at random is not a 10-room unit?

0.07 + 0.23 + 0.36 + 0.19 + 0.05 + 0.05 + 0.03 = 0.98

98% probability that a unit chosen at random is not a 10-room unit

(d) What is the probability that a unit chosen at random has less than five rooms?

7% probability it has 3 rooms

23% probability it has 4 rooms. So

7+23 = 30% probability that a unit chosen at random has less than five rooms

(e) What is the probability that a unit chosen at random has three rooms?

7% probability that a randomly chosen owner-occupied housing unit in a certain city has 3 rooms. So

7% probability that a unit chosen at random has less than five rooms

8 0
3 years ago
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