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Alex Ar [27]
3 years ago
7

What is "the square root of a number "

Mathematics
2 answers:
tiny-mole [99]3 years ago
8 0
Something times itself equals the square root
ex. 3x3=9 9x9=81
Reika [66]3 years ago
3 0
The square root of a number is the reversing of a squared number.
For example, 4 x 4 (or 4 squared) = 16.
The square root of 16 is 4.
I  hope this helps!
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a garage floor measures 150 feet by 120 feet. a scale drawing of the floor on grid paper uses a scale of one unit : 15 feet. wha
Nadya [2.5K]
1 unit = 15 feet

150 feet / 1 unit  = 150 / 15 = 10 units

120 feet / 1 unit = 120 / 15 = 8 units

The dimensions of the drawing equates :

10 units by 8 units .

hope this helps!

4 0
3 years ago
PLEASE RESPOND ASAP!!what is the value of z in the figure below??
Nookie1986 [14]

Answer:

126

Step-by-step explanation:

By cyclic quadrilateral theorem:

(180 \degree - 85 \degree) =  \frac{1}{2} (z \degree + 64 \degree) \\ 95 \degree \times 2 = z \degree + 64 \degree \\ 190 \degree = z \degree + 64 \degree \\ 190 \degree - 64 \degree = z \degree \\ 126\degree = z \degree \\ z = 126

4 0
3 years ago
Use stoke's theorem to evaluate∬m(∇×f)⋅ds where m is the hemisphere x^2+y^2+z^2=9, x≥0, with the normal in the direction of the
ludmilkaskok [199]
By Stokes' theorem,

\displaystyle\int_{\partial\mathcal M}\mathbf f\cdot\mathrm d\mathbf r=\iint_{\mathcal M}\nabla\times\mathbf f\cdot\mathrm d\mathbf S

where \mathcal C is the circular boundary of the hemisphere \mathcal M in the y-z plane. We can parameterize the boundary via the "standard" choice of polar coordinates, setting

\mathbf r(t)=\langle 0,3\cos t,3\sin t\rangle

where 0\le t\le2\pi. Then the line integral is

\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=\int_{t=0}^{t=2\pi}\mathbf f(x(t),y(t),z(t))\cdot\dfrac{\mathrm d}{\mathrm dt}\langle x(t),y(t),z(t)\rangle\,\mathrm dt
=\displaystyle\int_0^{2\pi}\langle0,0,3\cos t\rangle\cdot\langle0,-3\sin t,3\cos t\rangle\,\mathrm dt=9\int_0^{2\pi}\cos^2t\,\mathrm dt=9\pi

We can check this result by evaluating the equivalent surface integral. We have

\nabla\times\mathbf f=\langle1,0,0\rangle

and we can parameterize \mathcal M by

\mathbf s(u,v)=\langle3\cos v,3\cos u\sin v,3\sin u\sin v\rangle

so that

\mathrm d\mathbf S=(\mathbf s_v\times\mathbf s_u)\,\mathrm du\,\mathrm dv=\langle9\cos v\sin v,9\cos u\sin^2v,9\sin u\sin^2v\rangle\,\mathrm du\,\mathrm dv

where 0\le v\le\dfrac\pi2 and 0\le u\le2\pi. Then,

\displaystyle\iint_{\mathcal M}\nabla\times\mathbf f\cdot\mathrm d\mathbf S=\int_{v=0}^{v=\pi/2}\int_{u=0}^{u=2\pi}9\cos v\sin v\,\mathrm du\,\mathrm dv=9\pi

as expected.
7 0
3 years ago
Solve -2x-8&gt;3x+12<br><br> (Picture added, multiple choice)
QveST [7]
It will be c i showed how on paper

7 0
3 years ago
Fill in the missing numbers below.
Levart [38]

Answer:

5 feet + 12 inches = 2 yards

48 inches = 1 foot + 1 yard

5 feet = 3 feet + 24 inches

Step-by-step explanation:

To help solve these equations, you must know how to convert feet to inches, inches to yards, etc. Use the information below:

1 feet = 12 inches

3 feet = 1 yard

To solve 5 feet + 12 inches = blank yard(s), convert 5 feet & 12 inches to yards. Since 5 feet would be complicated to convert, let's convert 12 inches to feet first.

12 inches = 1 feet

Instead of 12 inches, we can substitute it as 5 feet + 1 feet = blank yard(s). That would be 6 feet = ? yards. 3 feet = 1 yard, which tells us we must divide both sides by 3. Thus, 5 feet + 12 inches = 2 yards.

Blank inches = 1 foot + 1 yard

To find the # of inches in a yard, you must first know that 3 feet = 1 yard. If there are 12 inches in a foot, we must multiply 3 by 12, getting us 36. You add 12 inches (1 foot), getting us 48 inches in total. Thus 48 inches = 1 foot + 1 yard.

Blank feet = 3 feet + 24 inches

Since 3 feet is already feet, we do not need to convert it. If 12 inches is 1 foot, we must divide 24 inches by 12. So, there is 2 feet in 24 inches. 2 + 3 is 5. Thus, 5 feet = 3 feet +24 inches.

8 0
3 years ago
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