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Alex Ar [27]
3 years ago
7

What is "the square root of a number "

Mathematics
2 answers:
tiny-mole [99]3 years ago
8 0
Something times itself equals the square root
ex. 3x3=9 9x9=81
Reika [66]3 years ago
3 0
The square root of a number is the reversing of a squared number.
For example, 4 x 4 (or 4 squared) = 16.
The square root of 16 is 4.
I  hope this helps!
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Can an acute and obtuse angle be supplementary? Draw a figure showing supplementary angles? ​
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Alexeev081 [22]
Number 4. will be a. because if you do 7*9=63*10=630.
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4 years ago
Read 2 more answers
Anyone know how to solve this?
vampirchik [111]

Answer:

10

Step-by-step explanation:

6 0
3 years ago
I have no idea!! Please help!!!
Ber [7]
The area of a traingle is \frac{1}{2}bh
So we need to know the base and the height
To work out the sides of a right angle triangle we can use a²+b²=c
c is the hypotenuse and a and b are the other sides
Because this triangle is isoceles we know that a and b are the same

a²+b²=c²
a²+a²=c²
2a²=c²
2a²=(x√6)²
2a²=(x√6)(x√6)
2a²=x²+x√6+x√6+6
2a²=x²+x√6+x√6+6
a²=\frac{x^{2}+x \sqrt{6}+x \sqrt{6}+6 }{2}
a=\sqrt{\frac{x^{2}+x\sqrt{6}+x\sqrt{6}+6}{2}}

A=\frac{1}{2}bh
A=\frac{1}{2}a*a
A=\frac{1}{2}×\sqrt{\frac{x^{2}+x\sqrt{6}+x\sqrt{6}+6}{2}}×\sqrt{\frac{x^{2}+x\sqrt{6}+x\sqrt{6}+6}{2}}
A=\frac{1}{2}×\frac{x^{2}+x \sqrt{6}+x \sqrt{6}+6 }{2}
A=\frac{x^{2}+x \sqrt{6}+x \sqrt{6}+6 }{4}
8 0
3 years ago
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