Can someone help me here pretty pls

Mathematics

1 answer:

IRINA_888 [86]2 years ago

7 0

5 minutes would be 290 and 8 minutes would be 464.

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The polynomial function y = x3 -3x2 + 16x - 48 has only one non-repeated x-intercept. What do you know about the complex zeros o

earnstyle [38]

• First way to solve:
We'll manipulate the expression of the equation:

$y=x^3-3x^2+16x-48\\\\ y=x^2(x-3)+16(x-3)\\\\ y=(x-3)(x^2+16)$

If we have y=0:

$x-3=0~~~or~~~x^2+16=0\\\\ x=3~~~or~~~x^2=-16\\\\ x=3~~~or~~~x=\pm\sqrt{-16}\\\\ x=3~~~or~~~x=\pm4i$

Then, the function has one real zero (x=3) and two imaginary zeros (4i and -4i).

Answer: B

• Second way to solve:

The degree of the function is 3. So, the function has 3 complex zeros.

Since the coefficients of the function are reals, the imaginary roots are in a even number (a imaginary number and its conjugated)

The function "has only one non-repeated x-intercept", then there is only one real zero.

The number of zeros is 3 and there is 1 real zero. So, there are 2 imaginary zeros.

Answer: B.

3 0

2 years ago

Distribute and simplify the radicals below (√12+6)(-√8-√2)

Hatshy [7]

For this case we have the following expression:

$(\sqrt {12} +6) (- \sqrt {8} - \sqrt {2})$

We apply distributive property:

$(\sqrt {12} * - \sqrt {8}) + (\sqrt {12} * - \sqrt {2}) + (6 * - \sqrt {8}) + (6 * - \sqrt {2} ) =\\- \sqrt {96} - \sqrt {24} -6 \sqrt {8} -6 \sqrt {2} =$

We rewrite in equivalent form:

$- \sqrt {4 ^ 2 * 6} - \sqrt {2 ^ 2 * 6} -6 \sqrt {2 ^ 2 * 2} -6 \sqrt {2} =\\-4 \sqrt {6} -2 \sqrt {6} -6 * 2 \sqrt {2} -6 \sqrt {2} =$

$-4 \sqrt {6} -2 \sqrt {6} -12 \sqrt {2} -6 \sqrt {2} =\\-6 \sqrt {6} -18 \sqrt {2}$

Answer:

$-6 \sqrt {6} -18 \sqrt {2}$

8 0

3 years ago

Read 2 more answers

Use Cramer's rule to find the solution to the following system of linear equations.

slavikrds [6]

Answer:

x = 53

y = 30

Step-by-step explanation:

Step(I):-

Given equations are

x -2y =-7 ...(I)

5x-9y =-5 ..(ii)

The matrix form AX = B

$\left[\begin{array}{ccc}1&-2\\ 5 & -9\\\end{array}\right] \left[\begin{array}{ccc}x\\y\\\end{array}\right] = \left[\begin{array}{ccc}-7\\-5\\\end{array}\right]$