T=650mi(hr/50mi)=13 hr

t-1=12 hr

12=650/(50+v) multiply both sides by 50+v

600+12v=650 subtract 600 from both sides

12v=50 divide both sides by 12

v=25/6 mph

v≈4.17mph

6 0

3 years ago

1<br>Prove that<br>1: sin/1-cot + cos/1-tan=cos+sin

Anit [1.1K]

Answer:

have:

$\frac{sin}{1-cot}+\frac{cos}{1-tan}\\\\=\frac{sin}{1-\frac{cos}{sin} }+\frac{cos}{1-\frac{sin}{cos} }\\\\=\frac{sin^{2} }{sin-cos}+\frac{cos^{2} }{cos-sin} \\\\=\frac{sin^{2} }{sin-cos}-\frac{cos^{2} }{cos-sin}\\\\=\frac{sin^{2}-cos^{2} }{sin - cos}\\\\=\frac{(sin-cos)(sin+cos)}{sin-cos}\\\\=sin+cos$

Step-by-step explanation:

4 0

3 years ago

Please help me The difference of two numbers is 9. If the larger number is one more than twice the smaller number, find the lage

Helen [10]

Answer:

Step-by-step explanation:

Let the larger number be represented by x

Let the smaller number be represented by y

from the question, the next equations can be gotten :

x - y = 9 equation 1

x = 1 + 2y equation 2

Substitute for x in equation 1

1 + 2y - y = 9

1 + y = 9

Collect like terms

y = 9 - 1

y = 8

Substitute for y in equation 1 and solve for x (the larger number)

x - 8 = 9

x = 9 + 8

x = 17

6 0

3 years ago