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ioda
3 years ago
14

HELPPP ME PLSSSS I NEED THIS FOR MY CLASS

Mathematics
1 answer:
Wewaii [24]3 years ago
7 0

Answer:

hii im looking at the same thing  you just have to do the multiplication on that

Step-by-step explanation:

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The combined area of a square and a rectangle is 225 square yards. the length of the rectangle is 8 times the width of the recta
snow_lady [41]

Answer:

The rectangle:  <u>L = 40 yards.   W = 5 yards</u>

The square: The length and width are both <u>5 yards</u>.

Step-by-step explanation:

<u>Let L and W be the length and width of the rectangle. </u>

<u>Let l and w be the length and width of the square.</u>

Area for each is:

Rectangle:  L*W

Square:       l*w

We are told that <u>L*W + l*w = 225 yards^2</u>

We are also told that

<u>L = 8W </u>

and that

<u>l = W</u>

Since the sides of a square are all equal, w is also W:  <u>w=W</u>

Summarizing and substituting:

L*W + l*w = 225 yards^2

(8W)*W + W*W = 225 yards^2

8W^2 + W^2 = 225 yards^2

9W^2  = 225 yards^2

W^2 = 25

W = 5 feet

---------------------

Therefore, since L = 8W <u>,</u> <u>L = 40 yards.   W = 5 yards</u> for the rectangle.

The square:  l=W, so <u>l = 5 yards, and thus w=5 yards</u>

--------------------------

Check:

Do a rectangle of 40' x 5' plus a square of 5' x 5' have a total combined area of 225 yards^2?

40yd x 5yd + 5yd x 5yd = 225 yards^2?

200 yd^2 + 25 yd^2 = 225 yards^2?

YES

5 0
2 years ago
The manager of a grocery store has selected a random sample of 100 customers. The average length of time it took these 100 custo
SSSSS [86.1K]

Answer:

The 95% confidence interval would be given by (2.804;3.196)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=3.0 represent the sample mean  

\mu population mean (variable of interest)

\sigma=1 represent the population standard deviation

n=100 represent the sample size  

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that z_{\alpha/2}=1.96

Now we have everything in order to replace into formula (1):

3.0-1.96\frac{1}{\sqrt{100}}=2.804    

3.0+1.96\frac{1}{\sqrt{10}}=3.196

So on this case the 95% confidence interval would be given by (2.804;3.196)    

4 0
3 years ago
What is the equation of the line that passes through the point (5,-2) and has a slope of 6/5?
noname [10]

Answer:

y=6/5x-8

Step-by-step explanation:

Hi there!

We want to find the equation of the line that passes through (5, -2) and has the slope of 6/5

We can write the equation of the line in slope-intercept form, which is y=mx+b, where m is the slope and b is the y intercept.

Since we are already given the slope of the line, we can immediately plug it into the equation:

y=6/5x+b

Now we need to find b

Since the equation passes through the point (5, -2), we can use it to solve for b

Substitute 5 as x and -2 as y:

-2=6/5(5)+b

Multiply

-2=6+b

Subtract 6 from both sides

-8=b

Substitute -8 as b.

y=6/5x-8

Hope this helps!

6 0
2 years ago
You have determined that a 60 percent learning curve is appropriate for a task. if your initial timing of person performing that
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C. 705.25 minutes
First, estimate the learning curve rate by calculating the average learning rate with each dou- bling of production
7 0
3 years ago
11.037 in word format
adell [148]
Eleven, three hundredths, and seven thousandths.
5 0
4 years ago
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