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Nina [5.8K]
3 years ago
8

Nicole receives 40 likes in 25 minutes assuming that the relationship is proportional how many like would she receive in 45 minu

tes
Mathematics
1 answer:
Mrac [35]3 years ago
3 0
He will receive 80 likes in 45 minutes
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A museum opened at 8:00 a.M. In the first hour, 350 prople purchased admission tickets. In the second hour, 20% more people purc
lianna [129]

Answer:

$13,475

Step-by-step explanation:

In the first hour:

350 people purchased admission tickets.

In the second hour:

20% MORE people purchased admission tickets.

Implication is, 20% of 350

= 20/ 100 * 350

simplifying that:

=2 * 35

=70

Therefore, 2nd hour purchase:

= 350 + 70

= 420 admission tickets.

TO GET THE TOTAL COST OF ADMISSION TICKETS BOUGHT, we Multiply the value of each admission tickets by the numbers of tickets bought.

1st hour Purchase = 350 * $17.50

= $6,125

2nd hour purchase = 420 * $17.50

= $7,350

Total amount of money paid for all the tickets purchased in the first two hours:

=$6125 + $7350

=$13,475

Enjoy! Maths is fun

8 0
3 years ago
Find the complement of the set given that
iris [78.8K]

Answer:

A ' = {-2,-1,0,1, 4,7}

Step-by-step explanation:

Here, the Universal set U is given as:

U = {x | x is in I and −3 ≤ x ≤ 7}

⇒ U = { -3,-2,-1,0,1,2,3,4,5,6,7}

Now given: A = {−3, 2, 3, 5, 6}

Compliment  A set of any set A is the set of all the elements which is in the universal set U but NOT in A.

So, here the set of elements which are in U but not in A  is

A ' = {-2,-1,0,1, 4,7}

So here the elements in the compliment of the given set -2,-1,0,1,4,7

4 0
2 years ago
Which equation models the trend line? y = -1.3x + 2 y = 1.3x + 2 y = -1.3x - 2 y + 1.3x - 2
tiny-mole [99]

Answer:

iomnjiujjii

Step-by-step explanation:

lio;

3 0
3 years ago
Find the limit
Lana71 [14]

Step-by-step explanation:

<h3>Appropriate Question :-</h3>

Find the limit

\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]

\large\underline{\sf{Solution-}}

Given expression is

\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]

On substituting directly x = 1, we get,

\rm \: = \: \sf \dfrac{1-2}{1 - 1}-\dfrac{1}{1 - 3 + 2}

\rm \: = \sf \: \: - \infty \: - \: \infty

which is indeterminant form.

Consider again,

\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]

can be rewritten as

\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( {x}^{2} - 3x + 2)}\right]

\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( {x}^{2} - 2x - x + 2)}\right]

\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( x(x - 2) - 1(x - 2))}\right]

\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x(x - 2) \: (x - 1))}\right]

\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ {(x - 2)}^{2} - 1}{x(x - 2) \: (x - 1))}\right]

\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ (x - 2 - 1)(x - 2 + 1)}{x(x - 2) \: (x - 1))}\right]

\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ (x - 3)(x - 1)}{x(x - 2) \: (x - 1))}\right]

\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ (x - 3)}{x(x - 2)}\right]

\rm \: = \: \sf \: \dfrac{1 - 3}{1 \times (1 - 2)}

\rm \: = \: \sf \: \dfrac{ - 2}{ - 1}

\rm \: = \: \sf \boxed{2}

Hence,

\rm\implies \:\boxed{ \rm{ \:\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right] = 2 \: }}

\rule{190pt}{2pt}

7 0
2 years ago
Read 2 more answers
Without calculating would 0.4+(2+0.6)be less than, greater than,or equal to 3? Explain
masya89 [10]
The answer would be “Greater than.”
3 0
3 years ago
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