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3 years ago

A cube has a volume of 7 to the 3rd power cubic centimeters . what is its surface area?

Mathematics

1 answer:

cricket20 [7]3 years ago

8 0

This cube has 6 faces, and all side lengths are equal.

The volume of a cube with sides of length L is given by L^3.

The problem says that the volume is 7^3, which means that each side is 7

The surface area of a cube of length L is 6*L^2. Since L = 7, the surface area is:

6*7^2 = 6*49 = 294 cm^2

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Digiron [165]

Answer:

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Step-by-step explanation:

Let the coordinates of Z be (x,y).

$\frac{x+5}{2}=-5 \implies x=-15 \\ \\ \frac{y+6}{2}=10 \implies y=14$

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2 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

Un polígono regular está inscrito en una circunferencia. ¿Qué medida del polígono es igual al radio de la circunferencia?

vlabodo [156]

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Step-by-step explanation:

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3 years ago

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garri49 [273]

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3 years ago

Read 2 more answers

You find an interest rate of 10% compounded quarterly. Calculate how much more money you would have in your pocket if you had us

Elena-2011 [213]

Answer:

see the explanation

Step-by-step explanation:

we know that

step 1

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$r=10\%=10/100=0.10\\n=4$

substitute in the formula above

$A=P(1+\frac{0.10}{4})^{4t}$

$A=P(1.025)^{4t}$

Applying property of exponents

$A=P[(1.025)^{4}]^{t}$

$A=P(1.1038)^{t}$

step 2

The formula to calculate continuously compounded interest is equal to

$A=P(e)^{rt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

e is the mathematical constant number

we have

$r=10\%=10/100=0.10$

substitute in the formula above

$A=P(e)^{0.10t}$

Applying property of exponents

$A=P[(e)^{0.10}]^{t}$

$A=P(1.1052)^{t}$

step 3

Compare the final amount

$P(1.1052)^{t} > P(1.1038)^{t}$

therefore

Find the difference

$P(1.1052)^{t} - P(1.1038)^{t}$ ----> Additional amount of money you would have in your pocket if you had used a continuously compounded account with the same interest rate and the same principal.

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3 years ago