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3 years ago

Choose the correct simplification of the expression (a^2/ b^3)^4.

Mathematics

1 answer:

anastassius [24]3 years ago

4 0

(a^2)^4 = a^8, and (b^3)^4 = b^12. Thus, the quotient is

a^8
--------
b^12

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find the coordinates of the points D ( 4, -4 ) and E ( 5, -5 ) after the transformation ( x; y ) ( x + 3, y -5

postnew [5]

Answer:

second option

Step-by-step explanation:

Given the rule

(x, y ) → (x + 3, y - 5)

This means add 3 to the original x- coordinate and subtract 5 from the original y- coordinate, that is

D(4, - 4 ) → D'(4 + 3, - 4 - 5 ) → D'(7, - 9 )

E(5, - 5 ) → E'(5 + 3, - 5 - 5 ) → E'(8, - 10 )

7 0

3 years ago

The third term in an arithmetic sequence is 10 and the fifth term is 26.If the first term is a1,which is an equation for the nth

dexar [7]

Just plug in 3 for n and then 5 for n to see if an turns out to be 10 and 26.

n=3:
A) an = 8*3+10 = 34
B) an = 8*3 - 14 = 10 OK
C) an = 16*3+10 = 58
D) an = 16*3 - 38 = 10 OK

n=5:
B) an = 8*5-14 = 26 OK
D) an = 16*5 - 38 = 42

So the answer is B

5 0

3 years ago

The Blue Ridge Parkway is 469 miles long. The parkway is a road that runs through 29 Virginia and North Carolina counties. Jenny

DedPeter [7]

Answer:

281/2/5 miles

Step-by-step explanation:

469/5 = 93.8

93.8x3 = 281.4

= 281/2/5 miles

Please mark as Brainliest, thank you!

8 0

3 years ago

Please help me do this!<br>both questions!

Simora [160]

Question a is 48 i think! because if you do 12 x how many side there are. it’s 4 so 12 x 4

7 0

2 years ago

Read 2 more answers

50 PTS ANSWER ALL <3333333

11Alexandr11 [23.1K]

QUESTION 33

The length of the legs of the right triangle are given as,

6 centimeters and 8 centimeters.

The length of the hypotenuse can be found using the Pythagoras Theorem.

${h}^{2} = {6}^{2} + {8}^{2}$

${h}^{2} = 36+ 64$

${h}^{2} = 100$

$h = \sqrt{100}$

$h = 10cm$

Answer: C

QUESTION 34

The triangle has a hypotenuse of length, 55 inches and a leg of 33 inches.

The length of the other leg can be found using the Pythagoras Theorem,

${l}^{2} + {33}^{2} = {55}^{2}$

${l}^{2} = {55}^{2} - {33}^{2}$

${l}^{2} = 1936$

$l = \sqrt{1936}$

$l = 44cm$

Answer:B

QUESTION 35.

We want to find the distance between,

(2,-1) and (-1,3).

Recall the distance formula,

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute the values to get,

$d=\sqrt{( - 1-2)^2+(3- - 1)^2}$

$d=\sqrt{( - 3)^2+(4)^2}$

$d=\sqrt{9+16}$

$d=\sqrt{25}$

$d = 5$

Answer: 5 units.

QUESTION 36

We want to find the distance between,

(2,2) and (-3,-3).

We use the distance formula again,

$d=\sqrt{( - 3-2)^2+( - 3- 2)^2}$

$d=\sqrt{( - 5)^2+( - 5)^2}$

$d=\sqrt{25+25}$

$d=\sqrt{50}$

$d=5\sqrt{2}$

Answer: D

8 0

3 years ago

Read 2 more answers