1)Use the provided information to identify each of Mr. Nicholson’s earning opportunities as arithmetic or geometric. For each op
portunity, include the common difference or ratio. In your final answer, use complete sentences to explain how you identified each opportunity as arithmetic or geometric. 2)Model each of Mr. Nicholson’s salary options with a recursive sequence that includes his potential earnings for the first three years of employment.
According to the first three terms of each sequence, can you conclude that there is a significant difference in Mr. Nicholson’s potential earnings with each increase option? Use complete sentences to explain your conclusion.
The missing provided information is that Mr. Nicholson accepts a job that pays an annual salary of
$60,000. And he is given the option of choosing between two annual raises:
a) an annual raise of $3,500 or b) an annual raise of 5% of his current salary.
Then, with that information you have to answer the given questions.Which I am going to do step by step.
<span>
1) identify each of Mr. Nicholson’s earning opportunities as arithmetic or
geometric. For each opportunity, include the common difference or
ratio. In your final answer, use complete sentences to explain how you
identified each opportunity as arithmetic or geometric.
- An annual raise of fix $3500 means that every year the salary increase in a constant amount driving to this sequence:
In this case, the increase is geometrical because you have that two adjacent terms differentiate by a constant factor, e.g.: 69,457.50 / 66,150 = 1.50.
2)Model each of Mr. Nicholson’s salary options with a recursive sequence
that includes his potential earnings for the first three years of
employment.
According to the first three terms of each sequence, can you conclude
that there is a significant difference in Mr. Nicholson’s potential
earnings with each increase option? Use complete sentences to explain
your conclusion.
Models
- Atrihmetic progression option
Annual salary the year n= Sn Initial Salary = S1 = 60,000 difference, d = 3500 number of year: n
Model: S = S1 + (n-1)*d
S = 60,000 + (n-1)*3500
Potential earnings for first three years:
You can use the fomula for the sum of n terms in an arithmetic progression: [S1 + S3]*(n) / (2)
Sum = [60,000 + 67000] * 3 / 2 = 190,500
This is the same that [60,000 + 63,500 + 67,000] = 190,500.
- Geometric progression:
S1 = 60,000 r = 1.05
Sn = S1 * r^(n-1) = 60,000 - (1.05)^(n-1)
Potential earnings the first three years:
60,000 + 63,000 + 66,150 = 189,150 </span> Now you got that there is a substantial difference in potential earnings with each option: the constant increase of $3500 (arithmetic progression) during three years results in a bigger earning for that time, because 5% of difference the second year is only 3000, and the third year 3150; both below $3500. This results in that the arithmetic progression is better for Mr. Nicholson during the first three years.
A flower garden in the form of trapezoid is shown. The length of longer base is labeled 18 feet, shorter base is 15 feet, height is 4 feet, and one leg is 5 feet.
Formula for perimeter of a trapezoid = Side a + side b + length a + length b
For the trapezium shown, its perimeter step 1,
we have to find the missing length
Length a
We are given height = 4 feet
Length of the longer base = 18 feet
Length of the shorter base = 15 feet
Different would give us the base of the right angle triangle
= 18 - 15 = 3 feet
Using Pythagoras Theorem we can find the side a = c
a² + b² = c²
3² + 4² = c²
9 + 16 = c²
c = √25
c = 5 feet
Hence side a = 5 feet
Perimeter of the Trapezoid shown =
18 feet + 15 feet + 5 feet + 5 feet
= 38 feet.
From the question,
You need two bottles of fertilizer to treat the flower garden shown. How many bottles do you need to treat a similar garden with a perimeter of 105 feet
Hence:
38 feet = 2 bottles
105 feet = x bottles
Cross y
= 38 × x = 105 × 2
= 38x = 105 × 2
x = 105 × 2/38
x = 26.25 bottles
26.25 bottles of fertilizer is needed to treat the garden with a perimeter of 105