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2 years ago

Give an example of a negative integer then give its opposite

Mathematics

1 answer:

9966 [12]2 years ago

8 0

Answer:

negative integer: -3

opposite: 3

Step-by-step explanation:

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Tickets to a play cost $5 at the door and $4 in advance. The theater club wants to raise at least $400 from the play. Write and

cestrela7 [59]

Your equation should be
$4(40 tickets) + $5(X) = $400
160 +5x = 400
-160 -160
0 5x = 340
divide both sides by 5
5x/5 = 340/5
x = 68

so they need to sell 68 tickets at the door.

4(40) + 5(68) = 400
160 + 340 + 400
400 + 400

7 0

2 years ago

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Degger [83]

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2 years ago

Liliana is renting a beach house for a family vacation. The house charges a $75 cleaning fee plus $95 per night. If Liliana want

Elenna [48]

95n+75 is less than or equal to 645. 645-75=570. 95n is less than or equal to 570. 570/95=6. A maximum of six nights

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2 years ago

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What is the solution to the system of linear equations?

Dmitry_Shevchenko [17]

Answer:

x = 5, y = -1/2

Step-by-step explanation:

3.5x - 5y = 20

3x + 4y = 13 multiply by 1.25 so the y's match up (you could match x's too)

3.75x + 5y = 16.25

–––––––––––––––––––––––

3.5x - 5y = 20

3.75x +5y = 16.25

7.25x + 0y = 36.25 you can add or subtract here (on this equation you add)

7.25x=36.25

x=5 So now we have x=5 and to find y we can just plug in x into one of the equations

–––––––––––––––––––

3(5) + 4y = 13

15 + 4y = 13

4y = -2

y = -1/2

x = 5, y = -1/2

Then you can plug in both to check your answers.

4 0

2 years ago

Find the length of the curve y = 3/5x^5/3 - 3/4x^1/3 + 6 for 1 < = x < = 8. The length of the curve is . (Type an exact an

Mashutka [201]

Answer:

$\sqrt\frac{387}{20}$

Step-by-step explanation:

$Arc Length =\int\limits^a_b {\sqrt{1+(\frac{dy}{dx})^2 } } \, dx$

$y=\dfrac{3}{5}x^{\frac{5}{3}}- \dfrac{3}{4}x^{\frac{1}{3}}+6$

$\frac{dy}{dx} =x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}}$

$1+(\frac{dy}{dx})^2 }=1+(x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}})^2\\=1+(x^{\frac{4}{3}}-\dfrac{1}{2}+ \dfrac{1}{16}x^{-\frac{4}{3}})$

$=\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}}$

For the Interval $1\leq x\leq 8$

Length of the Curve $=\int\limits^8_1 {\sqrt{\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}} } } \, dx\\$

Using T1-Calculator

$=\sqrt\frac{387}{20}$

3 0

3 years ago