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2 years ago

How fo you subtract unlike fractions?

2 answers:

5 0

For example if the problem is 4/3 subtracted by 2/4, you would make the denominators common

The gcf is 12 so you need to make both equal 12

2/4 x 3 = 6/12 and 4/3 x 4 = 16/12

16/12 - 6/10 = 10/12

djyliett [7]2 years ago

4 0

Make them the same denominator like 2/3 and 4/6 you can either simplify 4/6 t0 2/3 or do 2/2 * 2/3 and get 4/6

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Solve the system of equations algebraically.<br> 4x - 3y = 6<br> 6x - 5y = 6

muminat

Answer: x=6 y=6

Step-by-step explanation:

$\displaystyle\\\left \{ {{4x-3y=6} \atop {6x-5y=6}} \right.\\$

Since the right parts of the equation are equal, therefore the left parts of the equation are also equal:

$4x-3y=6x-5y\\4x-3y+5y=6x-5y+5y\\4x+2y=6x\\4x+2y-4x=6x-4x\\2y=2x\\$

Divide both parts of the equation by 2:

$y=x\\Hence,\\4x-3x=6\\x=6\\Thus,\\x=y=6$

3 0

1 year ago

What is 11 divided by 12 as a fraction

svlad2 [7]

11/12 as a fraction is 11/12; as a decimal it is ~ 0.9167

3 0

3 years ago

Gina measured the amount of water her friends drink each day in gallons. The line plot shows the measurements.

vova2212 [387]

Line plots are used to represent data using lines and dots

The difference between the greatest amount of water and the least is 1/2

From the line plot (see attachment), we have the following parameters:

$Least = 8\frac 28$

$Greatest = 8\frac 68$

<h3>Calculating the difference</h3>

The difference (d) is then calculated as:

$d =Greatest -Least$

So, we have:

$d =8\frac 68 -8\frac 28$

Subtract the common terms (8)

$d =\frac 68 -\frac 28$

Take LCM

$d =\frac {6-2}8$

$d =\frac {4}8$

Reduce the fraction

$d =\frac {1}2$

Hence, the difference between the greatest amount of water and the least is 1/2