4)input:5,6
output: 24,29
n+2
5) input : 1,2,3,4
output : -2,-4,-6,-8,-10,-12
-2n
6) input:5, 6
output: 2.5, 3
.5n
a^2+b^2=c^2 <----- the equation to find out sides for a right triangle
Answer:
The set of output values are (1,3,11,17) as Range
Step-by-step explanation:
Given function is f(x)=2x-3 and domain is (-1,0,4,7)
Function is given that taking set of input values from domain and give out set of output values.
For x=(-1)
f(x)=2x-3
f(-1)=2(-1)+3=(-2)+3=1
For x=0
f(x)=2x-3
f(0)=2(0)+3=3
For x=4
f(x)=2x-3
f(4)=2(4)+3=-8+3=11
For x=7
f(x)=2x-3
f(7)=2(7)+3=14+3=17
Thus,
The set of output values are (1,3,11,17) as Range
Answer:
A ≈ 78.5
Your answer was wrong because it said to round to the nearest tenth.
Step-by-step explanation:
First, to find the area of a circle, you need the radius or diameter of a circle. You can see that the radius is 5 (counting the units from E directly horizontal to the edge of the circle).
Area of a circle is:
A = πr²
A = π (5)²
Following PEMDAS (order of operations), you would do the exponent first:
A = π (25)
A ≈ 78.5
Answer:
56
Step-by-step explanation:
The thing to realize is that the total of both angles that have x in them is that they add to 145. That's given.
<LKM + <MKN = 145
2x + 10 + 4x - 3 = 145 Combine like terms
6x + 7 = 145 Subtract 7 from both sides
6x = 138 Divide by 6
x = 138/6
x = 23
That's not the answer.
2x + 10 = <LKM
2*23 + 10 = <LKM
46 + 10 = <LKM
56 = <LKM
