Answer:
0.32
Step-by-step explanation:
Let A be the event that the transferred ball was blue.
B be the event that the red ball is selected from box 2
C be the event that the transferred ball was red
Then:
P(A) be the probability that the transferred ball was blue, which is 3/8
P(C) be the probability that the transferred ball was red, which is 5/8
P(B|A) is the probability that selected ball is red, given that the transferred ball was blue, which is 4/7
P(B|C) is the probability that selected ball is red, given that the transferred ball was red, which is 5/7
P(B) is the probability that the selected ball is red, which there are 2 scenarios, given that the transferred ball is blue and red
P(B) = P(B|A)P(A) + P(B|C)P(C)
P(A|B) is the probability that the transferred ball was blue, given that a red ball is selected from Box 2, which can be solved using Bayes theorem