Answer:
10 boxes in the top row.
192 boxes in entire display.
Step-by-step explanation:
Let n be the number of rows.
Given:
Total number of rows = 8
Boxes in bottom row = 38
And each row has four fewer boxes than the row below it.
Solution:
Part A:
We know that the bottom row has 38 boxes and each row has four fewer boxes than the row below it.
Using below function for determining the number of boxes in each rows.

Where:
n = Number of row.
We need to find the boxes in the first row.
So, substitute n = 1 in above function.




Therefore, 10 boxes in the top row.
Part B:
Total boxes in the entire display.
Using formula as given below to determine the sum of the boxes in entire display.

Substitute n = 8, f(1) = 10 and f(8) = 38 in the above equation.




Therefore, 192 boxes in the entire display.
a. Answer: D: (∞, ∞)
R: (-∞, ∞)
<u>Step-by-step explanation:</u>
Theoretical domain is the domain of the equation (without an understanding of what the x-variable represents).
Theoretical range is the range of the equation given the domain.
c(p) = 25p
There are no restrictions on the p so the theoretical domain is All Real Numbers.
Multiplying 25 by All Real Numbers results in the range being All Real Numbers.
a) D: (∞, ∞)
R: (-∞, ∞)
*********************************************************************************
b. Answer: D: (0, 200)
R: (0, 5000)
<u>Step-by-step explanation:</u>
Practical domain is the domain of the equation WITH an understanding of what the x-variable represents.
Practical range is the range of the equation given the practical values of the domain.
The problem states that p represents the number of cups. Since we can't have a negative amount of cups, p ≥ 0. The problem also states that Bonnie will purchase a maximum of 200 cups. So, 0 ≤ p ≤ 200
The range is 25p → (25)0 ≤ (25)p ≤ (25)200
→ 0 ≤ 25p ≤ 5000
b) D: (0, 200)
R: (0, 5000)
Answer:

General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Geometry</u>
Area of a Rectangle: A = lw
<u>Calculus</u>
Derivatives
Derivative Notation
Implicit Differentiation
Differentiation with respect to time
Derivative Rule [Product Rule]: ![\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bd%7D%7Bdx%7D%20%5Bf%28x%29g%28x%29%5D%3Df%27%28x%29g%28x%29%20%2B%20g%27%28x%29f%28x%29)
Step-by-step explanation:
<u>Step 1: Define</u>
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<u>Step 2: Differentiate</u>
- [Area of Rectangle] Product Rule:

<u>Step 3: Solve</u>
- [Rate] Substitute in variables [Derivative]:

- [Rate] Multiply:

- [Rate] Add:

Topic: AP Calculus AB/BC (Calculus I/II)
Unit: Implicit Differentiation
Book: College Calculus 10e
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