Answer:
. 2 m/s
Step-by-step explanation:
Speed is defined as the rate of change in distance per time.
in this case you can simply observe the graph to get the final and initial distances & time.
The motion starts from 0 and moves to 2 if you look at the y axis of the graph.
Thus, the initial distance is 0m & the final distance is 2m
The time is specified in the question to have an initial of 0 sec and a final of 1 sec.
now let's plot our values out as a given.
S1 = 0m t1 = 0 sec
S2 = 2m t2 = 1 sec
and so you're going to have to find the change in time and displacement individually to later engage both in your formula which is - ∆V = ∆S / ∆t
∆S = S2 - S1 = 2m - 0m = 2m.
∆t = t2 - t1 = 1 sec - 0 sec = 1 sec.
∆V = ∆S / ∆t = 2m / 1 sec = 2m/sec (2m/s)
<span>You paint 1313 of a wall in 1414 hour.
Now we need to find the rate in order you to paint one wall.
1313 : 1414 = 1 : X
1414 = 1313 X
X = 1.08
So the rate per one wall is 1.08 hours.</span>
Answer:
Part 1) The solution is the point (-2,0)
Part 2) The solutions are the points (-2,0) and (0,2)
Step-by-step explanation:
Part 1
we have
-----> equation A
----> ---> equation B
Solve the system by graphing
Remember that the solution of the system is the intersection point both graphs
using a graphing tool
The solution is the point (-2,0)
see the attached figure N 1
Part 2
we have
-----> equation A
----> equation B
Solve the system by graphing
Remember that the solution of the system are the intersection points both graphs
using a graphing tool
The solutions are the points (-2,0) and (0,2)
see the attached figure N 2
There’s no photo for the triangle NET
Answer:
9/4
Step-by-step explanation: