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jeyben [28]
3 years ago
8

Can someone please help!!

Mathematics
1 answer:
valkas [14]3 years ago
5 0
Try to add up to 180°
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PLEASE HELPPPPP
umka21 [38]
The answer is B I believe
4 0
2 years ago
5 = 4a - 7<br> 3 - 8c = 35<br> -1/2x -7 = -11<br> Solve this please.
Hitman42 [59]

Answer:

a=3, c=-4, x=8

Step-by-step explanation:

5=4a-7

4a-7=5

4a=5+7

=12

a=12÷4

=3

3-8c=35

-8c=35-3

=32

c=-32÷8

=-4

-1/2x-7=-11

-1/2x=-11+7

=-4

x=4÷1/2

=4/1×2/1

=8

3 0
3 years ago
Can someone help me with this
Naya [18.7K]

Answer:

the answer should be 8.9

you square 12 and square the 8 and subtract them by each other

3 0
3 years ago
Read 2 more answers
Write and solve a real world problem involving the multiplication of a fraction and a whole number whose product is between 10 a
Fed [463]
A runner ran 1/2 of a mile for 24 days. How many miles did the runner run in all? (1/2×24=12) Therefore, the runner ran 12 miles in all in the course of 24 days.
4 0
3 years ago
each of the 20 balls is tossed independently and at random into one of the 5 bins. let p be the probability that some bin ends u
amm1812

if p is the probability that some bin ends up with 3 balls and q is the probability that every bin ends up with 4 balls. pq is 16.

First, let us label the bins with 1,2,3,4,5.

Applying multinomial distribution with parameters  n=20  and  p1=p2=p3=p4=p5=15  we find that probability that bin1 ends up with 3, bin2 with 5 and bin3, bin4 and bin5 with 4 balls equals:

5−2020!3!5!4!4!4!

But of course, there are more possibilities for the same division  (3,5,4,4,4)  and to get the probability that one of the bins contains 3, another 5, et cetera we must multiply with the number of quintuples that has one 3, one 5, and three 4's. This leads to the following:

p=20×5−2020!3!5!4!4!4!

In a similar way we find:

q=1×5−2020!4!4!4!4!4!

So:

pq=20×4!4!4!4!4!3!5!4!4!4!=20×45=16

thus, pq = 16.

To learn more about Probability visit: brainly.com/question/29508225

#SPJ4

7 0
1 year ago
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