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3 years ago

Given the relationship y equals 3x squared plus 1, if the input is 4 what is the output?

Mathematics

1 answer:

zheka24 [161]3 years ago

8 0

Answer:

Step-by-step explanation:

3x squared+1

x=4

But remember PEMDAS

So 4 squared which is 16

3(16)+1

3x 16= 48 +1= 49

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3 years ago

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Vilka [71]

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3 years ago

Find the equation of the plane that passes through the point (4,3,−2)(4,3,−2) and contains the line x(t)=−4−4t,y(t)=−1+3t,z(t)=1

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3 years ago

Solve the system by substitution.

kirill [66]

<h2>Answer:</h2>

x = 1

y = 1

<h3>Step-by-step explanation:</h3>

$y=-3x+4\\ y=x$

Substitute into one of the equations

$-3x+4=x$

Rearrange variables to the left sider of the equation

$-3x-x=-4$

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$-4x=-4$

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$x=\frac{-4}{-4}$

Determine the sign for multiplication or division

$x=\frac{4}{4}$

Cross out the common factor

$x=1$

Substitute into one of the equations

$y=1$

The solution of the system is

$\left \{ {{x=1} \atop {y=1}} \right.$

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2 years ago

Use the law of cosines to write an expression equivalent to b

andrezito [222]

Given:

A triangle ABC.

The given expression for b is:

$b=\sqrt{m+n-pq}$

To find:

The expression that is equivalent to b.

Solution:

According to the Law of Cosines,

$b^2=a^2+c^2-2ac\cos B$

It can be written as:

$b=\sqrt{a^2+c^2-2ac\cos B}$ ...(i)

We have,

$b=\sqrt{m+n-pq}$ ...(ii)

On comparing (i) and (ii), we get

$m=a^2$

$n=c^2$

$p=2ac$

$q=\cos B$

Therefore, the required values are $m=a^2,n=c^2,p=2ac,q=\cos B$ .

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3 years ago