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Damm [24]
4 years ago
10

Accuracy is the level of what​

Mathematics
1 answer:
ella [17]4 years ago
8 0
Accuracy is basically how close the given amount is to the actual amount
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Find the Quotient.<br>5,483 ÷ 4​
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1370.75

Step-by-step explanation:

6 0
3 years ago
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Please answer these two questions
Volgvan
The correct answer is two or four
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3 years ago
Two dice are rolled. Find the probability that the sum of the numbers on the two dice is 4.
photoshop1234 [79]
1/12

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4 0
3 years ago
What was the age distribution of prehistoric Native Americans? Extensive anthropological studies in the southwestern United Stat
neonofarm [45]

Answer:

\bar X = \frac{\sum_{i=1}^n X_i f_i}{n}= \frac{1394}{88}=15.8

s^2 = \frac{88(32372) -(1394)^2}{88(88-1}=118.3

Sd(X) = \sqrt{118.273}=10.9

Step-by-step explanation:

Previous concepts

In statistics and probability analysis, the expected value "is calculated by multiplying each of the possible outcomes by the likelihood each outcome will occur and then summing all of those values".

The variance of a random variable Var(X) is the expected value of the squared deviation from the mean of X, E(X).

And the standard deviation of a random variable X is just the square root of the variance.  

Solution to the problem

For this case we can calculate the properties required with the following table:

Interval     Mid point (x)     f           x*f         x^2 *f

_________________________________________

1-10               5.5               40        220         1210

11-20             15.5              15        232.5       3603.75

21-30            25.5             23       586.5       14955.75

>31                35.5             10        355          12602.5

________________________________________

Total                                 88        1394         32372

We assume that the mid point for the class >31 is 35.5 using the problem information.

For this case the expected value would be given by:

\bar X = \frac{\sum_{i=1}^n X_i f_i}{n}= \frac{1394}{88}=15.8

The variance owuld be given by this formula"

s^2 = \frac{n(\sum x^2 f) -(\sum xf)^2}{n(n-1}

And if we replace we got:

s^2 = \frac{88(32372) -(1394)^2}{88(88-1}=118.3

The standard deviation would be just the square root of the variance:

Sd(X) = \sqrt{118.273}=10.9

4 0
3 years ago
Read 2 more answers
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