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1 year ago

Write pqqqqrr in exponential form.

Mathematics

2 answers:

ANEK [815]1 year ago

5 0

p^1

q^4

r^2

Is this what your asking for and also can you please mark me as brainlist. Thank you

Lilit [14]1 year ago

4 0

Answer:

$p$ $q^{4}$ $r^{2}$

(so basically pq^4r^2)

Please vote for Brainliest and I hope this helps!

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Which of the following is a trinomial?

Masja [62]

Although you didn't provide any answer choices:

A trinomial is an expression with exactly three terms that can't be combined an example would be this

x^2 - 3x + 1

None of those terms can be combined

x^2 + 3 - 4 has three terms but it isn't considered a trinomial because you can simplify it to x^2 - 1 which is known as a binomial because it has 2 terms in it's simplified form.

hope this helps C:

5 0

3 years ago

Read 2 more answers

A cone has a radius of 5 cm and a height of 9 cm. What is the volume of the cone to the nearest whole number? Use 3.14 for pi.

Katyanochek1 [597]

Answer:

235or 236

Step-by-step explanation:

A cone has a radius of 5 cm

a height of 9 cm

Volume of cone =1/3πr^2h

=1/3×3.14×5×5×9

= 3.14×25×3

=3.14×75

=235.5

=235or 236 is the answer

8 0

2 years ago

Find the image of (-7,-3) reflected across the x-axis

Korvikt [17]

IF USING GEOMETRY...

x-axis = (x, -y)

Because the x does not have a negative sign the number DOES NOT change to its opposite form, but because the y has a negative sign the number DOES changes to its opposite form (from negative number to positive.)

So... if we use the formula of x-axis, which is (x, -y), the coordinates (-7,-3) would change to (-7, 3)

ANSWER (-7, 3)

3 0

2 years ago

A particular circle in the standard (x,y) coordinate

matrenka [14]

For any circle with Cartesian equation
$(x-a)^2 + (y-b)^2 = r^2$ ,
we have that the centre of the circle is $(a,b)$ , and the radius of the circle is $r$ .

So in the case that
$(x-5)^2 + y^2 = 38$ ,
we essentially have that
$a = 5, b = 0, r^2 = 38$ .

So the centre of the circle is $(5,0)$ , and the radius is $\sqrt{38}$ .

7 0

3 years ago

Thirty percent of all customers who enter a department store will make a purchase. Suppose that 6 customers enter the store and

torisob [31]

Answer:

Step-by-step explanation:

Let's use binomial distribution, because we are interested in find the total number of successes in a sequence of n independent experiments.

In probability, a binomial distribution is used in a Bernoulli process. That is, a sequence of experiments of n independent trials, each asking a dichotomous question, that means it only has two answers. One answer is a success (probability: p) and the other is a failure (probability: 1-p). In this case, every customer who enters in the store is the experiment. If they make a purchase is a success event, taking into account that every purchase decision has to be independent.

$P(X=x) = C(n,x)p^{x} (1-p)^{n-x}$

x= total number of success

n= total number of experiments

p=probability of success on an indivual trial

$C(n,x) = \frac{n!}{x!(n-x)!}$

a) x= 5 ------> customers that make a purchase

n= 6 ------> total customers

p=0.3

$p(X=5)= C(6,5)(0.3)^{5} (1-0.3)^{6-5} \\p(X=5)=0.102$

b) At least 3 customers make a purchase. x ≥ 3

$P(X\geq 3)=1-P (X=0)-P(X=1)-P(X=2)\\P(X\geq 3)=1-(C(6,0)(0.3^{0})(0.7)^{6}) - (C(6,1)(0.3^{1})(0.7)^{5}) - (C(6,2)(0.3^{2})(0.7)^{4})\\ P(X\geq 3) = 1-0.11765-0.30253-0.32414\\P(X\geq3)= 0.2557$

c) At most 2 customers make a purchase. x ≤ 2

$P(X\leq2) = P(X=0) + P(X=1) + P(X=2)\\P(X\leq2) = (C(6,0)(0.3^{0})(0.7)^{6}) + (C(6,1)(0.3^{1})(0.7)^{5}) + (C(6,2)(0.3^{2})(0.7)^{4})\\P(X\leq2) = 0.11765-0.30253-0.32414\\P(X\leq2)=0.7443$

d)At least 1 customer makes a purchase. x ≥ 1

$P(X\geq 1)=1-P(X=0)\\P(X\geq 1)= 1-C(0,6)(0.3)^{0}(0.7)^{6} \\P(X\geq 1)= 1-0.11765 = 0.8824$

e)They must be kind to customers, always willing to help and give information about products clearly and honestly.

Have enough inventory and offer promotions for the purchase of more than one product

Have an agile payment system that avoids rows and delays in purchases.

6 0

3 years ago