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marta [7]
3 years ago
6

3 / m + 4 - 4 / m = 6 (i) Show that this equation can be written as 6m^2 + 25m+16= 0

Mathematics
2 answers:
dem82 [27]3 years ago
8 0

Answer: Proved Below

Step-by-step explanation: Hence, Proved that  is equivalent to

Evgen [1.6K]3 years ago
6 0

Answer:

Proved Below

Step-by-step explanation:

\sf \frac{3}{m+4} - \frac{4}{m} = 6\\LCM = m(m+4)\\Multiplying \ both \ sides \ by\ m(m+4)\\3m - 4(m+4) = 6m(m+4)\\3m-4m-16 = 6m^2+24m\\-m-16 = 6m^2+24m\\Adding\ m\ to\ both\ sides\\-16 = 6m^2+24m+m\\-16 = 6m^2+25m\\Adding \ 16 \ to \ both \ sides\\0 = 6m^2+25m+16\\OR\\6m^2+25m+16 = 0

Hence, Proved that \sf \frac{3}{m+4} - \frac{4}{m} = 6 is equivalent to \sf 6m^2+25m+16 = 0.

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Vertical Asymptote:

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we are given

f(x)=log_3(x-1)

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we know that vertical asymptotes are values of x where f(x) becomes +inf or -inf

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so, we can set value inside log to zero

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we know that

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For finding horizontal asymptote , we find lim x-->inf or -inf

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