The y-intercept is the value of y when x is equal to zero. From the equation,
y = 500 + 50x
the y-intercept is calculated by:
y = 500 + 50(0) = 500
Therefore, the correct answer is option B. The y-intercept is 500; it represents the one-time campaign fee.
In order to use the simple interest formula, we first define the variables. The interest would be equal to Samuel's desired amount $ 2,488 minus the principal amount of $ 1,800 which is then equal to $ 688. The rate must be in decimal form which is equal to 0.12 while t is expressed in years. Substituting the values, t is equal to 3. Thus, it will take 36 <span>months for Samuel's account balance to reach $2,448. </span>
7x+4<46
7x+4(-4)<46(-4) <- Subtraction Property of Equality
7x<42
7x(/7)<42(/7) <- Division Property of Equality
x<6
I hope this helps!
~kaikers
Answer:
(a) 315°
(b) 3°
(c) 238°
Step-by-step explanation:
Bearings are measured clockwise from north. The triangle described is illustrated in the attachment.
<h3>(a)</h3>
The bearing of P from R is 180° different from the bearing of R from P it will be ...
135° +180° = 315° . . . . bearing of P from R
__
<h3>(b)</h3>
The bearing of Q from R is 48° more than the bearing of P from R, so is ...
315° +48° = 363°, or 3° . . . . bearing of Q from R
__
<h3>(c)</h3>
The angle QPR has a value that makes the sum of angles in the triangle equal to 180°. It is ...
180° -48° -55° = 77°
The bearing of Q from P is 77° less than the bearing of R from P, so is ...
135° -77° = 58°
As above, the reverse bearing from Q to P is ...
58° +180° = 238° . . . . bearing of P from Q
1. Given any triangle ABC with sides BC=a, AC=b and AB=c, the following are true :
i) the larger the angle, the larger the side in front of it, and the other way around as well. (Sine Law) Let a=20 in, then the largest angle is angle A.
ii) Given the measures of the sides of a triangle. Then the cosines of any of the angles can be found by the following formula:
a^{2}=b ^{2}+c ^{2}-2bc(cosA)
2.
20^{2}=9 ^{2}+13 ^{2}-2*9*13(cosA) 400=81+169-234(cosA) 150=-234(cosA) cosA=150/-234= -0.641
3. m(A) = Arccos(-0.641)≈130°,
4. Remark: We calculate Arccos with a scientific calculator or computer software unless it is one of the well known values, ex Arccos(0.5)=60°, Arccos(-0.5)=120° etc
