All categories

4 years ago

Someone please help??

Mathematics

1 answer:

Sidana [21]4 years ago

8 0

4 is the correct answer as 4th root of 1296 is 6

You might be interested in

LORAN is a long range hyperbolic navigation system. Suppose two LORAN transmitters are located at the coordinates (−60,0) and (6

USPshnik [31]

LORAN follows an hyperbolic path.

The equation of the hyperbola is: $\mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}$

The coordinates are given as:

$\mathbf{(x,y) = (-60,0)\ (60,0)}$

The center of the hyperbola is

$\mathbf{(h,k) = (0,0)}$

The distance from the center to the focal points is given as:

$\mathbf{c = 60}$

Square both sides

$\mathbf{c^2 = 3600}$

The distance from the receiver to the transmitters is given as:

$\mathbf{2a = 100}$

Divide both sides by 2

$\mathbf{a = 50}$

Square both sides

$\mathbf{a^2 = 2500}$

We have:

$\mathbf{b^2 = c^2 - a^2}$

This gives

$\mathbf{b^2 = 3600 - 2500}$

$\mathbf{b^2 = 1100}$

The equation of an hyperbola is:

$\mathbf{\frac{(x - h)^2}{a^2} + \frac{(y - k)^2}{b^2} = 1}$

So, we have:

$\mathbf{\frac{(x - 0)^2}{2500} + \frac{(y - 0)^2}{1100} = 1}$

$\mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}$

Hence, the equation of the hyperbola is: $\mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}$

Read more about hyperbolas at:

brainly.com/question/15697124

7 0

3 years ago

Read 2 more answers

What is the scale factor? Answer Choices 4 21 .25 1.4

Anestetic [448]

Answer:

The answer would be 4

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Factor completely.

lidiya [134]

$9 \times {x}^{2} - 25 \\ = 9 {x}^{2} - 25 \\ = (3x - 5)(3x + 5)$

Answer is D.

Hope this helps. - M

4 0

4 years ago

Read 2 more answers

In a school of 200 students, 90 students are in the marching band, 145 students are on sports teams and 75 students participate

mars1129 [50]

Answer:

Step-by-step explanation:

3 0

3 years ago

Use the segment addition postulate to write three equations using the diagram below

creativ13 [48]

Answer:

$PQ + QR = PR$ => equation 1

$RS + ST = RT$ => equation 2

$PR + RT = PT$ => equation 3

Step-by-step explanation:

Points P, Q, R, S, and T are collinear therefore, the following equations can be written based on the segment addition postulate:

$PQ + QR = PR$ => equation 1

$RS + ST = RT$ => equation 2

$PR + RT = PT$ => equation 3

More equations can actually be written from the diagram given using the segment addition postulate. Such as:

$PQ + QR + RS + ST = PT$

8 0

3 years ago