Answer
3.25x − y/5 + 1/2
Step-by-step explanation:
1) For our first job, PROBLEM A, it has a mean of 515 points and a standard deviation of 114 points. We're given the goal of calculating what % belongs between 401 and 629. As we can see, if we remove 515, then subtract 114 from 515, we obtain our first value of 401, then if we add our standard deviation tournament, we get our second number of 629. So, using the empirical rule, we know that in this scenario, 68 of our data points will fall inside this range.
2) Part B requires us to identify the scores that are less than 401 and larger than 629. So, in part A, we have the inclusive section of this, and now we have the exclusive section. Simply remove 60 percent from 100 percent, and we get 32 percent outside of this range.
Answer:
x=3 and y=
4 / 3 (Fraction)
Step-by-step explanation:
Substitute x for 6y-5.
2(6y−5)−3y=2
Add 6y and 3y, and multiply 5 by 2/Simplify the equation.
9y−10=2
Add 10 to both sides, and then divide each side by 9.
9y−10+10=2+10
9y / 9 = 12 / 9
y = 4/3.
Repeat the process but replace y with 4/3!
Hello!!! The equation that will have same solution as 4A-12=27 would be
4(a-3)=27!!!
Also for number 2 2(y-3)=4 would be
2y-3=4
3. Same solution as -5m+4=6 is
-5m+3+1=6
HOPE HELPED HAV A GOOD DAYYYYY <3
Answer: 92
Step-by-step explanation:
Formula : Sum of first n numbers = Average x n
Given: Average score on first 6 tests= 84
A score on all 8 tests = 86
Then, Sum of first 6 numbers = 84 x 6 = 504
Sum of first 8 numbers = 86 x 8 = 688
Sum of two last numbers = (Sum of first 8 numbers) - (Sum of first 6 numbers)
= 688-504
=184
Average of last two numbers = (Sum of two last numbers )÷2
= 184÷2
= 92
Hence, the average of your last two test scores = 92.