Figure A is a scale image of figure B. Figure A maps to figure B with scale factor of 0.25.

When a particular type of thumbtack is dropped, it will land point up (A flat-top thumbtack resting on its flat top) or point

erma4kov [3.2K]

Answer:

0.48

0.52

No

Yes

Step-by-step explanation:

Result of experiment :

Point up = 48

Point down = 52

Total number of trials = 100

Recall :

Experimental probability = number of outcomes / number of trials

1.)

P(Landing point up) = 48 / 100 = 0.48

2.)

P(Landing point down) = 52 / 100 = 0.52

3.)

The same result will not occur has the outcomes of trials aren't fixed.

4.) Yes, nearly the same result could occur on the second trial, as the number of possible outcubes are just 2 and the number if trials is high.

8 0

3 years ago

This my last one help

Lerok [7]

Answer:

A2 = 120

A3 = 60

A5 = 60

A6 = 120

Step-by-step explanation:

Angle 1 and 2 are supplementary, so A2 = 180 - 60, which is 120.

Angle 1 and 3 are vertical angles, which are always the same measure.

Angle 5 is alternate interior angles with 3, which means it is also 60.

Angle 6 is alternate interior angles with 4, which means it is 120.

3 0

3 years ago

The length of a rectangle is 5 ft less than three times the width, and the area of the rectangle is 50 ft². Find the dimensions

Mariulka [41]

Answer

Length = 10 ft

Width = 5 ft

Explanation

Area of the rectangle given = 50 ft²

Let the width of the rectangle be x

So this means the length of the rectangle will be 3x - 5

What to find:

The dimensions of the rectangle.

Step-by-step solution:

Area of a rectangle = length x width

i.e A = L x W

Put A = 50, L = 3x - 5, W = x into the formula.

$\begin{gathered} 50=(3x-5)x \\ 50=3x^2-5x \\ 3x^2-5x-50=0 \end{gathered}$

The quadratic equation can now be solve using factorization method:

$\begin{gathered} 3x^2-5x-50=0 \\ 3x^2-15x+10x-50=0 \\ 3x(x-5)+10(x-5)=0 \\ (3x+10)(x-5)=0 \\ 3x+10=0\text{ }or\text{ }x-5=0 \\ 3x=-10\text{ }or\text{ }x=5 \\ x=-\frac{10}{3}\text{ }or\text{ }x=5 \end{gathered}$

Since the dimension can not be negative, hence the value of x will be = 5.

Therefore, the dimensions of the rectangle will be:

$\begin{gathered} Length=3x-5=3(5)-5=15-5=10\text{ }ft \\ \\ Width=x=5\text{ }ft \end{gathered}$

7 0

1 year ago

What are the coordinates of the x-intercepts of the parabola y = x² - 8x + 15?

tamaranim1 [39]

Answer:

(3, 0) and (5, 0)

Step-by-step explanation:

we have

$y=x^{2}-8x+15$

we know that

The x-intercepts are the values of x when the value of y is equal to zero

so

For y=0

$x^{2}-8x+15=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2}-8x+15=0$

so

$a=1\\b=-8\\c=15$

substitute in the formula

$x=\frac{-(-8)\pm\sqrt{-8^{2}-4(1)(15)}} {2(1)}$

$x=\frac{8\pm\sqrt{4}} {2}$

$x=\frac{8\pm2} {2}$

$x=\frac{8+2} {2}=5$

$x=\frac{8-2} {2}=3$

so

x=3, x=5

therefore

The x-intercepts are (3,0) and (5,0)

4 0

3 years ago

If a scale drawing has a scale of 1 centimetre to 4 meters which measurements are correct

andrew-mc [135]

Answer: Statements 2 and 3

Step-by-step explanation:

On a drawing scale;

1cm - 4m

4CM - 16M (MULTIPLYING BY 4)

6cm - 24m (multiplying by 6)

7cm - 28m (multiplying by 7)

8cm - 32m (multiplying by 8)

9CM - 36M (MULTIPLYING BY 9)

3 0

4 years ago