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Nostrana [21]
3 years ago
10

i will give best answer a right rectangular prism is shown What shape best describes the cross section cut at an angle to the ba

se of a right rectangular prism? Trapezoid Parallelogram Square Rectangle
Mathematics
2 answers:
Vikentia [17]3 years ago
8 0

Answer:

parallelogram

Step-by-step explanation:

did the test

balu736 [363]3 years ago
4 0

Answer:

parallelogram

Step-by-step explanation:

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Which instruments listed below are examples of the classification idiophone?
rjkz [21]
Idiophone means an instrument that will produce a sound when being struck.
so the answer is B.
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2 years ago
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Find the midpoint M of a segment with the given endpoints.<br> A(-4, 6) and B(2,8)
yan [13]

Answer:

(-1, 7)

Step-by-step explanation:

We'll use the midpoint formula: ([x₁ + x₂]/2, [y₁ + y₂]/2)

x₁ = -4

x₂ = 2

y₁ = 6

y₂ = 8

Our equation will look like this

([-4 + 2]/2, [6 + 8]/2)

( -2/2, 14/2 )

(-1, 7)

4 0
2 years ago
Suppose that u = &lt; u1,u2 &gt; and v = &lt; v1,v2 &gt; are vectors such that | u+v |^2 = | u |^2 + | v |^2. Prove that u and v
AveGali [126]

If u= (u1,u2,u3) andv= (v1,v2,v3), then the dot product of u and v is u·v=u1v1+u2v2+u3v3. For instance, the dot product of u=i−2j−3kandv= 2j−kisu·v= 1·0 + (−2)·2 + (−3)(−1) =−1.

Properties of the Dot Product.

Let u,v, and w be three vectors and let c be a real number. Then u·v=v·u,(u+v)·w=u·w+v·w,(cu)·v=c(u·v).

Further, u·u=|u|2.  

Thus, if u=0is the zerovector, then u·u= 0, and otherwise u·u>0.1

Orthogonality Two vectors u and v are said to be  orthogonal(perpendicular), if the angle between them is 90◦.Theorem. Two vectors u and v are orthogonal if and only if u·v= 0.

7 0
3 years ago
What’s the answer ... ?
Elan Coil [88]
44 and 52 is the answer
4 0
3 years ago
Round to nearest tenth and solve for x
stepladder [879]

Answer:

\displaystyle 9,6

Step-by-step explanation:

\displaystyle \frac{x}{6,4} = csc\:42 \hookrightarrow 6,4cot\:42 = x \hookrightarrow 9,5646499191... = x \\ \\ 9,6 ≈ x

<em>OR</em>

\displaystyle \frac{6,4}{x} = sin\:42 \hookrightarrow xsin\:42 = 6,4 \hookrightarrow \frac{6,4}{sin\:42} = x \hookrightarrow 9,5646499191... = x \\ \\ 9,6 ≈ x

Information on trigonometric ratios

\displaystyle \frac{OPPOCITE}{HYPOTENUSE} = sin\:θ \\ \frac{ADJACENT}{HYPOTENUSE} = cos\:θ \\ \frac{OPPOCITE}{ADJACENT} = tan\:θ \\ \frac{HYPOTENUSE}{ADJACENT} = sec\:θ \\ \frac{HYPOTENUSE}{OPPOCITE} = csc\:θ \\ \frac{ADJACENT}{OPPOCITE} = cot\:θ

I am joyous to assist you at any time.

6 0
2 years ago
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