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USPshnik [31]
2 years ago
10

A bag contains 7 pieces of paper numbered 1 to 7. P(2)=. Is

Mathematics
1 answer:
pochemuha2 years ago
5 0

Answer:

P (2) =\frac{1}{7}  Theoretical probability

Step-by-step explanation:

The theoretical probability is defined as:

P = \frac{number\ of\ desired\ results}{number\ of\ possible\ results}

In this case we look for the probability of taking a 2 out of the bag. As there is only one paper with the number 2 in the bag then:

number of desired results = 1

The amount of paper in the bag is equal to 7, so:

number of possible results = 7

Thus:

P (2) =\frac{1}{7}

This is a theoretical probability, since we do not need to perform the experiment to calculate the probability.

To calculate the experimental probability we must perform the following experiment:

Take a paper out of the bag, record the number obtained and then return the paper to the bag.

Now repeat this experiment n times. (Perform n trials)

So:

P (2) = \frac{number\ of\ times\ you\ obtained\ the\ number\ 2}{number\ of\ trials\ performed}

To calculate a theoretical probability you always need to perform an experiment with n trials.

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An identification code is to consist of 3 letters followed by 2 digits. Determine the following
kirill [66]
Well let's see:

The first letter can be any one of 26 .
       For each one . . .
The second letter can be any one of the remaining 25.
       For each one . . .
The third letter can be any one of the remaining 24.
       For each one . . .
The two digits can be any number from 01 to 98 ...
       except 11, 22, 33, 44, 55, 66, 77, or 88.  (No repetition.)
      There are 90 of them.

So the total number of possibilities is    (26 · 25 · 24 · 90) .

When I multiply that out, I get   1,404,000 .

I don't know how you got your number, so I can't comment on your
method, but I did find something interesting about your number:

If I assume that you did the three letters the same way I did, then
if I divide your number by  (26·25·24), the quotient will show me
how you handled the two digits.

                         1,263,600 / (26·25·24)  =  81 .

That's very intriguing, because it's so close to the 90 sets of digits
that I used.  But I don't know what it means, or if it means anything
at all.
7 0
3 years ago
Read 2 more answers
Help quickly please
Margarita [4]
Weathering-the process of wearing or being worn by long exposure to the atmosphere.
3 0
3 years ago
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A random sample of size n1= 25, taken from a normal population with a standard deviation σ1= 5, has a mean X1= 80. A second rand
sesenic [268]

Answer:

The 94% confidence interval would be given by 2.898 \leq \mu_1 -\mu_2 \leq 7.102

Step-by-step explanation:

Previous concepts  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X_1 =80 represent the sample mean 1

\bar X_2 =75 represent the sample mean 2

n1=25 represent the sample 1 size  

n2=36 represent the sample 2 size  

\sigma_1 =5 sample standard deviation for sample 1

\sigma_2 =3 sample standard deviation for sample 2

\mu_1 -\mu_2 parameter of interest.

The confidence interval for the difference of means is given by the following formula:  

(\bar X_1 -\bar X_2) \pm z_{\alpha/2}\sqrt{\frac{\sigma^2_1}{n_1}+\frac{\sigma^2_2}{n_2}} (1)  

The point of estimate for \mu_1 -\mu_2 is just given by:

\bar X_1 -\bar X_2 =80-75=5

Since the Confidence is 0.94 or 94%, the value of \alpha=0.06 and \alpha/2 =0.03, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.03,0,1)".And we see that z_{\alpha/2}=1.88  

The standard error is given by the following formula:

SE=\sqrt{\frac{\sigma^2_1}{n_1}+\frac{\sigma^2_2}{n_2}}

And replacing we have:

SE=\sqrt{\frac{5^2}{25}+\frac{3^2}{36}}=1.118

Confidence interval

Now we have everything in order to replace into formula (1):  

5-1.88\sqrt{\frac{5^2}{25}+\frac{3^2}{36}}=2.898  

5+1.8\sqrt{\frac{6^2}{36}+\frac{7^}{49}}=7.102  

So on this case the 94% confidence interval would be given by 2.898 \leq \mu_1 -\mu_2 \leq 7.102  

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evablogger [386]
The one above is right.
5 0
3 years ago
Is all negative numbers intergers ?
kobusy [5.1K]

Answer:

Yes. Intergers are all whole numbers so negative whole numbers are included too.

Step-by-step explanation:

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